int object is not iterable?

Question

inp = int(input("Enter a number:"))

for i in inp:
    n = n + i;
    print (n)

... throws an error: 'int' object is not iterable

I wanted to find out the total by adding each digit, for eg, 110. 1 + 1 + 0 = 2. How do I do that?

Thanks

Answer 1

As ghills had already mentioned

inp = int(input("Enter a number:"))

n = 0
for i in str(inp):
    n = n + int(i);
    print n

When you are looping through something, keyword is "IN", just always think of it as a list of something. You cannot loop through a plain integer. Therefore, it is not iterable.

Answer 2

Take your input and make sure it's a string so that it's iterable.

Then perform a list comprehension and change each value back to a number.

Now, you can do the sum of all the numbers if you want:

inp = [int(i) for i in str(input("Enter a number:"))]
print sum(inp)

Or, if you really want to see the output while it's executing:

def printadd(x,y):
    print x+y
    return x+y

inp = [int(i) for i in str(input("Enter a number:"))]
reduce(printadd,inp)

Answer 3

First, lose that call to int - you're converting a string of characters to an integer, which isn't what you want (you want to treat each character as its own number). Change:

inp = int(input("Enter a number:"))

to:

inp = input("Enter a number:")

Now that inp is a string of digits, you can loop over it, digit by digit.

Next, assign some initial value to n -- as you code stands right now, you'll get a NameError since you never initialize it. Presumably you want n = 0 before the for loop.

Next, consider the difference between a character and an integer again. You now have:

n = n + i;

which, besides the unnecessary semicolon (Python is an indentation-based syntax), is trying to sum the character i to the integer n -- that won't work! So, this becomes

n = n + int(i)

to turn character '7' into integer 7, and so forth.

Answer 4

Well, you want to process the string representing the number, iterating over the digits, not the number itself (which is an abstract entity that could be written differently, like "CX" in Roman numerals or "0x6e" hexadecimal (both for 110) or whatever).

Therefore:

inp = input('Enter a number:')

n = 0
for digit in inp:
     n = n + int(digit)
     print(n)

Note that the n = 0 is required (someplace before entry into the loop). You can't take the value of a variable which doesn't exist (and the right hand side of n = n + int(digit) takes the value of n). And if n does exist at that point, it might hold something completely unrelated to your present needs, leading to unexpected behaviour; you need to guard against that.

This solution makes no attempt to ensure that the input provided by the user is actually a number. I'll leave this problem for you to think about (hint: all that you need is there in the Python tutorial).

Answer 5

One possible answer to OP-s question ("I wanted to find out the total by adding each digit, for eg, 110. 1 + 1 + 0 = 2. How do I do that?") is to use built-in function divmod()

num = int(input('Enter a number: ')
nums_sum = 0

while num:
    num, reminder = divmod(num, 10)
    nums_sum += reminder