I had tried several times using prepared statements but it returns SQL exception. here is my code:
public ArrayList<String> name(String mobile, String password) {
ArrayList<String> getdata = new ArrayList<String>();
PreparedStatement stmt = null;
try {
String login = "select mobile, password from tbl_1 join tbl_2 on tbl_1.fk_id=2.Pk_ID where mobile=? and password=?";
String data = "select * from tbl_2 where password='" + password + "'";
PreparedStatement preparedStatement = conn.prepareStatement(login);
preparedStatement.setString(1, mobile);
preparedStatement.setString(1, password);
ResultSet rs = preparedStatement.executeQuery(login);
Statement stmts = (Statement) conn.createStatement();
if (rs.next()) {
System.out.println("Db inside RS");
ResultSet data = stmts.executeQuery(data);
while (data.next()) { /* looping through the resultset */
getdata.add(data.getString("name"));
getdata.add(data.getString("place"));
getdata.add(data.getString("age"));
getdata.add(data.getString("job"));
}
}
} catch (Exception e) {
System.out.println(e);
}
return getdata;
}
While running this, I got the following SQL exception:
com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '? and password=?' at line 1.
Any suggestion to make this work? any piece of code is appreciated.
You need to use:
instead of
when you pass in a string to
executeQuery()
that query is executed literally and thus the?
is send to the database which then creates the error. By passing query string you are not execution the "cached" prepared statement for which you passed the values.For both parameter you use
preparedStatement.setString(1, ..);
so the first parameter is set two times. but you never set the value for second parameter.so change
to