Sql query for tree table

2020-01-28 03:56发布

I have a table with tree structure:

id parentId name
----------------
1  0        Category1
2  0        Category2
3  1        Category3
4  2        Category4
5  1        Category5
6  2        Category6
7  3        Category7

In sql query resut I need a table like:

id parentId level name
----------------------
1  0        0     Category1
3  1        1     Category3
7  3        2     Category7
5  1        1     Category5
2  0        0     Category2
4  2        1     Category4
6  2        1     Category6

Who can help me to write ms-sql query? Thanks!

2条回答
Evening l夕情丶
2楼-- · 2020-01-28 04:31

Expanding on a_horse_with_no_name's answer, this show how to use SQL Server's implementation of recursive CTE (recursive single-record cross apply) in combination with row_number() to produce the exact output in the question.

declare @t table(id int,parentId int,name varchar(20))
insert @t select 1,  0        ,'Category1'
insert @t select 2,  0,        'Category2'
insert @t select 3,  1,        'Category3'
insert @t select 4 , 2,        'Category4'
insert @t select 5 , 1,        'Category5'
insert @t select 6 , 2,        'Category6'
insert @t select 7 , 3,        'Category7'
;

WITH tree (id, parentid, level, name, rn) as 
(
   SELECT id, parentid, 0 as level, name,
       convert(varchar(max),right(row_number() over (order by id),10)) rn
   FROM @t
   WHERE parentid = 0

   UNION ALL

   SELECT c2.id, c2.parentid, tree.level + 1, c2.name,
       rn + '/' + convert(varchar(max),right(row_number() over (order by tree.id),10))
   FROM @t c2 
     INNER JOIN tree ON tree.id = c2.parentid
)
SELECT *
FROM tree
order by RN

To be honest, using the IDs themselves to produce the tree "path" would work, since we are ordering directly by id, but I thought I'd slip in the row_number() function.

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Fickle 薄情
3楼-- · 2020-01-28 04:36
WITH tree (id, parentid, level, name) as 
(
   SELECT id, parentid, 0 as level, name
   FROM your_table
   WHERE parentid = 0

   UNION ALL

   SELECT c2.id, c2.parentid, tree.level + 1, c2.name
   FROM your_table c2 
     INNER JOIN tree ON tree.id = c2.parentid
)
SELECT *
FROM tree;

I have currently no SQL Server at hand to test it, so there might be some typos (syntax errors) in there

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