How to open a website when a Button is clicked in

Question

I am designing an app, with several button for users to click on. Once button is clicked, user is directed to appropriate website. How do I accomplish this?

Answer 1

you can use this on your button click activity

Intent webOpen = new Intent(android.content.Intent.ACTION_VIEW);
            WebOpen.setData(Uri.parse("http://www.google.com"));
                startActivity(myWebLink);

and import this on your code

import android.net.Uri;

Answer 2

ImageView Button = (ImageView)findViewById(R.id.button);

Button.setOnClickListener(new OnClickListener() {

    public void onClick(View v) {
        Uri uri = Uri.parse("http://google.com/");

        Intent intent = new Intent(Intent.ACTION_VIEW, uri);
        startActivity(intent);
    }
});

Answer 3

I just need one line to show a website in my app:

startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse("http://match4app.com")));

Answer 4

Add this to your button's click listener:

  Intent intent = new Intent(android.content.Intent.ACTION_VIEW);
    try {
        intent.setData(Uri.parse(url));
        startActivity(intent);
    } catch (ActivityNotFoundException exception) {
        Toast.makeText(getContext(), "Error text", Toast.LENGTH_SHORT).show();
    }

If you have a website url as a variable instead of hardcoded string then don't forget to handle an ActivityNotFoundException and show error. Or you may receive invalid url and app will simply crash. (Pass random string instead of url variable and see for youself )

Answer 5

If you are talking about an RCP app, then what you need is the SWT link widget.

Here is the official link event handler snippet.

Update

Here is minimalist android application to connect to either superuser or stackoverflow with 2 buttons.

package ap.android;

import android.app.Activity;
import android.content.Intent;
import android.net.Uri;
import android.os.Bundle;
import android.view.View;

public class LinkButtons extends Activity {

    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.main);
    }

    public void goToSo (View view) {
        goToUrl ( "http://stackoverflow.com/");
    }

    public void goToSu (View view) {
        goToUrl ( "http://superuser.com/");
    }

    private void goToUrl (String url) {
        Uri uriUrl = Uri.parse(url);
        Intent launchBrowser = new Intent(Intent.ACTION_VIEW, uriUrl);
        startActivity(launchBrowser);
    }

}

And here is the layout.

<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:orientation="vertical" android:layout_width="fill_parent" android:layout_height="fill_parent">
    <TextView android:layout_width="fill_parent" android:layout_height="wrap_content" android:text="@string/select" />
    <Button android:layout_height="wrap_content" android:clickable="true" android:autoLink="web" android:cursorVisible="true" android:layout_width="match_parent" android:id="@+id/button_so" android:text="StackOverflow" android:linksClickable="true" android:onClick="goToSo"></Button>
    <Button android:layout_height="wrap_content" android:layout_width="match_parent" android:text="SuperUser" android:autoLink="web" android:clickable="true" android:id="@+id/button_su" android:onClick="goToSu"></Button>
</LinearLayout>

Time permitting, I'll add the site logos to the buttons to make it a bit sexier ;-)

Answer 6

You can wrap the buttons in anchors that href to the appropriate website.

<a href="http://www.stackoverflow.com">
  <input type="button" value="Button" />
</a>
<a href="http://www.stackoverflow.com">
  <input type="button" value="Button" />
</a>
<a href="http://www.stackoverflow.com">
  <input type="button" value="Button" />
</a>

When the user clicks the button (input) they are directed to the destination specified in the href property of the anchor.

Edit: Oops, I didn't read "Eclipse" in the question title. My mistake.