What's the Rust idiom to define a field pointi

Question

Given a struct:

#[repr(C)]
pub struct User {
    pub name: *const c_char,
    pub age: u8,
    pub ctx: ??,
}

the field ctx would only be manipulated by C code; it's a pointer to a C struct UserAttr.

According to the Rust FFI documentation, the choice would be defined as an opaque type pub enum UserAttr {}. However, I found that Rust is unable to copy its value, e.g. why does the address of an object change across methods.

What's the right way in Rust to define such an opaque pointer, so that its value (as a pointer) gets copied across methods?

Answer 1

The future

RFC 1861 introduced the concept of an extern type. While implemented, it is not yet stabilized. Once it is, it will become the preferred implementation:

#![feature(extern_types)]

extern "C" {
    type Foo;
}

type FooPtr = *mut Foo;

Today

The documentation states:

To do this in Rust, let’s create our own opaque types:

#[repr(C)] pub struct Foo { private: [u8; 0] }
#[repr(C)] pub struct Bar { private: [u8; 0] }

extern "C" {
    pub fn foo(arg: *mut Foo);
    pub fn bar(arg: *mut Bar);
}

By including a private field and no constructor, we create an opaque type that we can’t instantiate outside of this module. An empty array is both zero-size and compatible with #[repr(C)]. But because our Foo and Bar types are different, we’ll get type safety between the two of them, so we cannot accidentally pass a pointer to Foo to bar().

An opaque pointer is created such that there's no normal way of creating such a type; you can only create pointers to it.

mod ffi {
    use std::ptr;

    pub struct MyTypeFromC { _private: [u8; 0] }

    pub fn constructor() -> *mut MyTypeFromC {
        ptr::null_mut()
    }

    pub fn something(_thing: *mut MyTypeFromC) {
        println!("Doing a thing");
    }
}

use ffi::*;

struct MyRustType {
    score: u8,
    the_c_thing: *mut MyTypeFromC,
}

impl MyRustType {
    fn new() -> MyRustType {
        MyRustType {
            score: 42,
            the_c_thing: constructor(),
        }
    }

    fn something(&mut self) {
        println!("My score is {}", self.score);
        ffi::something(self.the_c_thing);
        self.score += 1;
    }
}

fn main() {
    let mut my_thing = MyRustType::new();
    my_thing.something();
}

Breaking it down a bit:

// opaque -----V~~~~~~~~~V
          *mut MyTypeFromC
//        ^~~^ ------------ pointer

Thus it's an opaque pointer. Moving the struct MyRustType will not change the value of the pointer.

The past

Previous iterations of this answer and the documentation suggested using an empty enum (enum MyTypeFromC {}). An enum with no variants is semantically equivalent to the never type (!), which is a type that cannot exist. There were concerns that using such a construct could lead to undefined behavior, so moving to an empty array was deemed safer.