You should not use <Link> outside a

2020-01-27 04:04发布

I'm trying to set up react-router in an example application, and I'm getting the following error:

You should not use <Link> outside a <Router>

My app is set up like so:

Parent component

const router = (
  <div className="sans-serif">
    <Router histpry={browserHistory}>
      <Route path="/" component={Main}>
        <IndexRoute component={PhotoGrid}></IndexRoute>
        <Route path="/view/:postId" component={Single}></Route>
      </Route>
    </Router>
  </div>
);

render(<Main />, document.getElementById('root'));

Child/Main component

export default () => (
  <div>
    <h1>
      <Link to="/">Redux example</Link>
    </h1>
  </div>
)

Any idea what I'm doing wrong here?

Here's a Sandbox link to demonstrate the problem.

9条回答
别忘想泡老子
2楼-- · 2020-01-27 04:17

Make it simple:

render(<BrowserRouter><Main /></BrowserRouter>, document.getElementById('root'));

and don't forget: import { BrowserRouter } from "react-router-dom";

查看更多
干净又极端
3楼-- · 2020-01-27 04:19

I was getting this error because I was importing a reusable component from an npm library and the versions of react-router-dom did not match.

So make sure you use the same version in both places!

查看更多
【Aperson】
4楼-- · 2020-01-27 04:22

I'm assuming that you are using React-Router V4, as you used the same in the original Sandbox Link.

You are rendering the Main component in the call to ReactDOM.render that renders a Link and Main component is outside of Router, that's why it is throwing the error:

You should not use <Link> outside a <Router>

Changes:

  1. Use any one of these Routers, BrowserRouter/HashRouter etc..., because you are using React-Router V4.

  2. Router can have only one child, so wrap all the routes in a div or Switch.

  3. React-Router V4, doesn't have the concept of nested routes, if you wants to use nested routes then define those routes directly inside that component.


Check this working example with each of these changes.

Parent Component:

const App = () => (
  <BrowserRouter>
    <div className="sans-serif">
      <Route path="/" component={Main} />
      <Route path="/view/:postId" component={Single} />
    </div>
  </BrowserRouter>
);

render(<App />, document.getElementById('root'));

Main component from route

import React from 'react';
import { Link } from 'react-router-dom';

export default () => (
  <div>
    <h1>
      <Link to="/">Redux example</Link>
    </h1>
  </div>
)

Etc.


Also check this answer: Nested routes with react router v4

查看更多
叛逆
5楼-- · 2020-01-27 04:26

I kinda come up with this code :

import React from 'react';
import { render } from 'react-dom';

// import componentns
import Main from './components/Main';
import PhotoGrid from './components/PhotoGrid';
import Single from './components/Single';

// import react router
import { Router, Route, IndexRoute, BrowserRouter, browserHistory} from 'react-router-dom'

class MainComponent extends React.Component {
  render() {
    return (
      <div>
        <BrowserRouter history={browserHistory}>
          <Route path="/" component={Main} >
            <IndexRoute component={PhotoGrid}></IndexRoute>
            <Route path="/view/:postId" component={Single}></Route>
          </Route>
        </BrowserRouter>
      </div>
    );
  }
}

render(<MainComponent />, document.getElementById('root'));

I think the error was because you were rendering the Main component, and the Main component didn't know anything about Router, so you have to render its father component.

查看更多
地球回转人心会变
6楼-- · 2020-01-27 04:29

If you don't want to change much, use below code inside onClick()method.

this.props.history.push('/');
查看更多
疯言疯语
7楼-- · 2020-01-27 04:30

Whenever you try to show a Link on a page thats outside the BrowserRouter you will get that error.

This error message is essentially saying that any component that is not a child of our <Router> cannot contain any React Router related components.

You need to migrate your component hierarchy to how you see it in the first answer above. For anyone else reviewing this post who may need to look at more examples.

Let's say you have a Header.jscomponent that looks like this:

import React from 'react';
import { Link } from 'react-router-dom';

const Header = () => {
    return (
        <div className="ui secondary pointing menu">
            <Link to="/" className="item">
                Streamy
            </Link>
            <div className="right menu">
                <Link to="/" className="item">
                    All Streams
                </Link>
            </div>
        </div>
    );
};

export default Header;

And your App.js file looks like this:

import React from 'react';
import { BrowserRouter, Route, Link } from 'react-router-dom';
import StreamCreate from './streams/StreamCreate';
import StreamEdit from './streams/StreamEdit';
import StreamDelete from './streams/StreamDelete';
import StreamList from './streams/StreamList';
import StreamShow from './streams/StreamShow';
import Header from './Header';

const App = () => {
  return (
    <div className="ui container">
      <Header />
      <BrowserRouter>
        <div>
        <Route path="/" exact component={StreamList} />
        <Route path="/streams/new" exact component={StreamCreate} />
        <Route path="/streams/edit" exact component={StreamEdit} />
        <Route path="/streams/delete" exact component={StreamDelete} />
        <Route path="/streams/show" exact component={StreamShow} />
        </div> 
      </BrowserRouter>
    </div>
  );
};

export default App;

Notice that the Header.js component is making use of the Link tag from react-router-dom but the componet was placed outside the <BrowserRouter>, this will lead to the same error as the one experience by the OP. In this case, you can make the correction in one move:

import React from 'react';
import { BrowserRouter, Route } from 'react-router-dom';
import StreamCreate from './streams/StreamCreate';
import StreamEdit from './streams/StreamEdit';
import StreamDelete from './streams/StreamDelete';
import StreamList from './streams/StreamList';
import StreamShow from './streams/StreamShow';
import Header from './Header';

const App = () => {
  return (
    <div className="ui container">
      <BrowserRouter>
        <div>
        <Header />
        <Route path="/" exact component={StreamList} />
        <Route path="/streams/new" exact component={StreamCreate} />
        <Route path="/streams/edit" exact component={StreamEdit} />
        <Route path="/streams/delete" exact component={StreamDelete} />
        <Route path="/streams/show" exact component={StreamShow} />
        </div> 
      </BrowserRouter>
    </div>
  );
};

export default App;

Please review carefully and ensure you have the <Header /> or whatever your component may be inside of not only the <BrowserRouter> but also inside of the <div>, otherwise you will also get the error that a Router may only have one child which is referring to the <div> which is the child of <BrowserRouter>. Everything else such as Route and components must go within it in the hierarchy.

So now the <Header /> is a child of the <BrowserRouter> within the <div> tags and it can successfully make use of the Link element.

查看更多
登录 后发表回答