I have a problem with Python threading and sending a string in the arguments.
def processLine(line) :
print "hello";
return;
.
dRecieved = connFile.readline();
processThread = threading.Thread(target=processLine, args=(dRecieved));
processThread.start();
Where dRecieved is the string of one line read by a connection. It calls a simple function which as of right now has only one job of printing "hello".
However I get the following error
Traceback (most recent call last):
File "C:\Python25\lib\threading.py", line 486, in __bootstrap_inner
self.run()
File "C:\Python25\lib\threading.py", line 446, in run
self.__target(*self.__args, **self.__kwargs)
TypeError: processLine() takes exactly 1 arguments (232 given)
232 is the length of the string that I am trying to pass, so I guess its breaking it up into each character and trying to pass the arguments like that. It works fine if I just call the function normally but I would really like to set it up as a separate thread.
You're trying to create a tuple, but you're just parenthesizing a string :)
Add an extra ',':
Or use brackets to make a list:
If you notice, from the stack trace:
self.__target(*self.__args, **self.__kwargs)
The
*self.__args
turns your string into a list of characters, passing them to theprocessLine
function. If you pass it a one element list, it will pass that element as the first argument - in your case, the string.I hope to provide more background knowledge here.
First, constructor signature of the of method threading::Thread:
Second, A quirk in Python about
tuple
:On the other hand, a string is a sequence of characters, like
'abc'[1] == 'b'
. So if send a string toargs
, even in parentheses (still a sting), each character will be treated as a single parameter.However, Python is so integrated and is not like JavaScript where extra arguments can be tolerated. Instead, it throws an
TypeError
to complain.