How to create a table corresponding to enum in EF6

2020-01-26 21:09发布

I've followed MSDN on how to handle enumerations in Code First for EF6. It worked, as supposed to but the field in the created table that refers to the enumerator is a simple int.

I'd prefer a second table to be produced, the values of which would follow the definition of the enumerator in C# code. So, instead of only getting a table corresponding to Department in the example on MSDN, I'd also like to see a second table populated by the items from Faculty.

public enum Faculty { Eng, Math, Eco }     

public partial class Department 
{ 
  [Key] public Guid ID { get; set; } 
  [Required] public Faculty Name { get; set; } 
}

Researching the issue, I stumbled upon a solution, which suggests creating a table for the enumeration and populating it explicitly by seeding.

It appear to me as a cumbersome approach and a lot of work that should be handled automagically. After all, the system knows what actual values that constitute the enumeration. From DB point of view it's still data rows, just as the entities that I create but from OO aspect, it's not really a data - rather a type (loosely expressed) that can assume a finite and onbeforehand known number of states.

Is the approach of populating the table "manually" recommended?

7条回答
疯言疯语
2楼-- · 2020-01-26 21:34

Another approach that works (and feels simpler to me) in EF Core:

Your Enum

public enum Color
{
    Red = 1,
    Blue = 2,
    Green = 3,
}

Db Tables

public class CustomObjectDto
{
    public int ID { get; set; }

    // ... other props

    public Color ColorID { get; set; }
    public ColorDto ColorDto { get; set; }
}

public class ColorDto
{
    public Color ID { get; set; }
    public string Name { get; set; }
}

Your DbContext

public class Db : DbContext
{
    public Db(DbContextOptions<Db> options) : base(options) { }

    public DbSet<CustomObjectDto> CustomObjects { get; set; }
    public DbSet<ColorDto> Colors { get; set; }

    protected override void OnModelCreating(ModelBuilder modelBuilder)
    {
        // Seed database with all Colors
        foreach (Color color in Enum.GetValues(typeof(Color)).Cast<Color>())
        {
            ColorDto colorDto = new ColorDto
            {
                ID = color,
                Name = color.ToString(),
            };

            modelBuilder.Entity<ColorDto>().HasData(colorDto);
        }
    }
}

In code I basically only use the enum Color (never ColorDto). But it's still nice to have the 'Colors' table with an FK in the 'CustomObjects' table for sql queries and views.

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女痞
3楼-- · 2020-01-26 21:38

Based on @Alberto Monteiro answer i've created generic class in case when you have several tables. The notice here is that Id is the type of TEnum. Using it in such way will provide option to use Enum for declaring property type.

public class Question
{
    public QuestionTypeEnum QuestionTypeId { get; set; } // field property

    public QuestionType QuestionType { get; set; } // navigation property
}

By default Enum using integers, so the db provider will create field with "int" type.

EnumTable.cs

    public class EnumTable<TEnum>
        where TEnum : struct
    {
        public TEnum Id { get; set; }
        public string Name { get; set; }

        protected EnumTable() { }

        public EnumTable(TEnum enumType)
        {
            ExceptionHelpers.ThrowIfNotEnum<TEnum>();

            Id = enumType;
            Name = enumType.ToString();
        }

        public static implicit operator EnumTable<TEnum>(TEnum enumType) => new EnumTable<TEnum>(enumType);
        public static implicit operator TEnum(EnumTable<TEnum> status) => status.Id;
    }

ExceptionHelpers.cs

static class ExceptionHelpers
{
    public static void ThrowIfNotEnum<TEnum>()
        where TEnum : struct
    {
        if (!typeof(TEnum).IsEnum)
        {
            throw new Exception($"Invalid generic method argument of type {typeof(TEnum)}");
        }
    }
}

Now you just can inherit the EnumTable

public enum QuestionTypeEnum
{
    Closed = 0,
    Open = 1
}

public class QuestionType : EnumTable<QuestionTypeEnum>
{
    public QuestionType(QuestionTypeEnum enumType) : base(enumType)
    {
    }

    public QuestionType() : base() { } // should excplicitly define for EF!
}

Seed the values

context.QuestionTypes.SeedEnumValues<QuestionType, QuestionTypeEnum>(e => new QuestionType(e));
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疯言疯语
4楼-- · 2020-01-26 21:40

Another possibility, if you want to keep your model simpler, POCO style, use the enum as a property that will be stored as an integer by entity framework.

Then, if you want the "enum tables" to be created and updated in your DB, I recommend using the nuget package https://github.com/timabell/ef-enum-to-lookup and use it in a EF Migration seed method for example:

public enum Shape
{
    Square,
    Round
}

public class Foo
{
    public int Id { get; set; }
    public Shape Shape { get; set; }
}

public class MyDbContext : DbContext
{
    public DbSet<Foo> Foos { get; set; }
}

using(var context = new MyDbContext())
{
    var enumToLookup = new EnumToLookup
    {
        TableNamePrefix = string.Empty,
        NameFieldLength = 50,
        UseTransaction = true
    };
    enumToLookup.Apply(context);
}

This will create the "Shape" table with 2 rows named Square and Round, with the relevant foreign key constraint in the table "Foo"

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Root(大扎)
5楼-- · 2020-01-26 21:42

Alberto Monteiro answered this very well. I had to make a few adjustments to get it to work with EF core.

Rename your enum and add description decorators

public enum FacultyEnum 
{
    [Description("English Professor")]
    Eng, 
    [Description("Math Professor")]
    Math, 
    [Description("Economics Professor")]
    Eco 
}

Create a class that represent the table

public class Faculty
{
    private Faculty(FacultyEnum @enum)
    {
        Id = (int)@enum;
        Name = @enum.ToString();
        Description = @enum.GetEnumDescription();
    }

    protected Faculty() { } //For EF

    [Key, DatabaseGenerated(DatabaseGeneratedOption.None)]
    public int Id { get; set; }

    [Required, MaxLength(100)]
    public string Name { get; set; }

    [MaxLength(100)]
    public string Description { get; set; }

    public static implicit operator Faculty(FacultyEnum @enum) => new Faculty(@enum);

    public static implicit operator FacultyEnum(Faculty faculty) => (FacultyEnum)faculty.Id;
}

Your model reference the class

public class ExampleClass
{
    public virtual Faculty Faculty { get; set; }
}

Create a extension method to get description from enum and seed values

using System;
using System.ComponentModel;
using System.Data.Entity;
using System.Data.Entity.Migrations;
using System.Linq;

public static class Extensions
{
    public static string GetEnumDescription<TEnum>(this TEnum item)
        => item.GetType()
               .GetField(item.ToString())
               .GetCustomAttributes(typeof(DescriptionAttribute), false)
               .Cast<DescriptionAttribute>()
               .FirstOrDefault()?.Description ?? string.Empty;
}

Add the seed in YourDbContext.cs

protected override void OnModelCreating(ModelBuilder modelBuilder)
    {
        modelBuilder.Entity<Faculty>().HasData(FacultyEnum.Eng, FacultyEnum.Math, FacultyEnum.Eco);
    }

Add the enum table in your DbContext

public class MyClass : DbContext
{
    public DbSet<ExampleClass> Examples { get; set; }
    public DbSet<Faculty> Facultys { get; set; }
}

Use it

var example = new ExampleClass();
example.Faculty = FacultyEnum.Eng;

if (example.Faculty == FacultyEnum.Math)
{
    //code
}

To remember

If you don't add virtual in Faculty property, you must use Include method from DbSet to do Eager Load

var exampleFromDb = dbContext.Examples.Include(x => x.Faculty).SingleOrDefault(e => e.Id == 1);
if (example.Faculty == FacultyEnum.Math)
{
    //code
}

If Faculty property is virtual, then just use it

var exampleFromDb = dbContext.Examples.Find(1);
if (example.Faculty == FacultyEnum.Math)
{
    //code
}
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淡お忘
6楼-- · 2020-01-26 21:50

Excellent @AlbertoMonterio! To get this to work with ASP.NET CORE / EF Core I made a few adjustments to Alberto's solution.

For brevity, only the modifications are shown below:

Create a extension method to get description from enum and seed values

using System;
using System.ComponentModel;
using System.Data.Entity;
using System.Data.Entity.Migrations;
using System.Linq;
using Microsoft.EntityFrameworkCore; //added
using Microsoft.EntityFrameworkCore.Metadata.Builders; //added

public static class Extensions
{
    //unchanged from alberto answer
    public static string GetEnumDescription<TEnum>(this TEnum item)
        => item.GetType()
               .GetField(item.ToString())
               .GetCustomAttributes(typeof(DescriptionAttribute), false)
               .Cast<DescriptionAttribute>()
               .FirstOrDefault()?.Description ?? string.Empty;

    //changed
    public static void SeedEnumValues<T, TEnum>(this ModelBuilder mb, Func<TEnum, T> converter)
    where T : class => Enum.GetValues(typeof(TEnum))
                           .Cast<object>()
                           .Select(value => converter((TEnum)value))
                           .ToList()
                            .ForEach(instance => mb.Entity<T>().HasData(instance));
}

Add the seed in Configuration.cs

Add Seeding to OnModelCreating of DataContext

protected override void OnModelCreating(ModelBuilder builder)
{
    builder.SeedEnumValues<Faculty, EnumEntityRole>(e => e);
}
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女痞
7楼-- · 2020-01-26 21:55

Since EF doesn't handle it automatically, yes, this is the recommend way.

I suggest some modifications in article that you provided.

Rename your enum

public enum FacultyEnum { Eng, Math, Eco }

Create a class that represent the table

public class Faculty
{
    private Faculty(FacultyEnum @enum)
    {
        Id = (int)@enum;
        Name = @enum.ToString();
        Description = @enum.GetEnumDescription();
    }

    protected Faculty() { } //For EF

    [Key, DatabaseGenerated(DatabaseGeneratedOption.None)]
    public int Id { get; set; }

    [Required, MaxLength(100)]
    public string Name { get; set; }

    [MaxLength(100)]
    public string Description { get; set; }

    public static implicit operator Faculty(FacultyEnum @enum) => new Faculty(@enum);

    public static implicit operator FacultyEnum(Faculty faculty) => (FacultyEnum)faculty.Id;
}

Your model reference the class

public class ExampleClass
{
    public virtual Faculty Faculty { get; set; }
}

Create a extension method to get description from enum and seed values

using System;
using System.ComponentModel;
using System.Data.Entity;
using System.Data.Entity.Migrations;
using System.Linq;

public static class Extensions
{
    public static string GetEnumDescription<TEnum>(this TEnum item)
        => item.GetType()
               .GetField(item.ToString())
               .GetCustomAttributes(typeof(DescriptionAttribute), false)
               .Cast<DescriptionAttribute>()
               .FirstOrDefault()?.Description ?? string.Empty;

    public static void SeedEnumValues<T, TEnum>(this IDbSet<T> dbSet, Func<TEnum, T> converter)
        where T : class => Enum.GetValues(typeof(TEnum))
                               .Cast<object>()
                               .Select(value => converter((TEnum)value))
                               .ToList()
                               .ForEach(instance => dbSet.AddOrUpdate(instance));
}

Add the seed in Configuration.cs

protected override void Seed(Temp.MyClass context)
{
    context.Facultys.SeedEnumValues<Faculty, FacultyEnum>(@enum => @enum);
    context.SaveChanges();
}

Add the enum table in your DbContext

public class MyClass : DbContext
{
    public DbSet<ExampleClass> Examples { get; set; }
    public DbSet<Faculty> Facultys { get; set; }
}

Use it

var example = new ExampleClass();
example.Faculty = FacultyEnum.Eng;

if (example.Faculty == FacultyEnum.Math)
{
    //code
}

To remember

If you don't add virtual in Faculty property, you must use Include method from DbSet to do Eager Load

var exampleFromDb = dbContext.Examples.Include(x => x.Faculty).SingleOrDefault(e => e.Id == 1);
if (example.Faculty == FacultyEnum.Math)
{
    //code
}

If Faculty property is virtual, then just use it

var exampleFromDb = dbContext.Examples.Find(1);
if (example.Faculty == FacultyEnum.Math)
{
    //code
}
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