How to deserialize a JObject to .NET object

2020-01-26 17:54发布

I happily use the Newtonsoft JSON library. For example, I would create a JObject from a .NET object, in this case an instance of Exception (might or might not be a subclass)

if (result is Exception)
    var jobjectInstance = JObject.FromObject(result);

now I know the library can deserialize JSON text (i.e. a string) to an object

// only works for text (string)
Exception exception = JsonConvert.DeserializeObject<Exception>(jsontext); 

but what I am looking for is:

// now i do already have an JObject instance
Exception exception = jobjectInstance.????

Well it is clear that I can go from on JObject back to JSON text and then use the deserialize functionality, but that seems backwards to me.

3条回答
Explosion°爆炸
2楼-- · 2020-01-26 18:24

Too late, just in case some one is looking for another way:

void Main()
{
    string jsonString = @"{
  'Stores': [
    'Lambton Quay',
    'Willis Street'
  ],
  'Manufacturers': [
    {
      'Name': 'Acme Co',
      'Products': [
        {
          'Name': 'Anvil',
          'Price': 50
        }
      ]
    },
    {
      'Name': 'Contoso',
      'Products': [
        {
          'Name': 'Elbow Grease',
          'Price': 99.95
        },
        {
          'Name': 'Headlight Fluid',
          'Price': 4
        }
      ]
    }
  ]
}";

    Product product = new Product();
    //Serializing to Object
    Product obj = JObject.Parse(jsonString).SelectToken("$.Manufacturers[?(@.Name == 'Acme Co' && @.Name != 'Contoso')]").ToObject<Product>();

    Console.WriteLine(obj);
}


public class Product
{
    public string Name { get; set; }
    public decimal Price { get; set; }
}
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地球回转人心会变
3楼-- · 2020-01-26 18:28

According to this post, it's much better now:

// pick out one album
JObject jalbum = albums[0] as JObject;

// Copy to a static Album instance
Album album = jalbum.ToObject<Album>();

Documentation: Convert JSON to a Type

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够拽才男人
4楼-- · 2020-01-26 18:34

From the documentation I found this

JObject o = new JObject(
   new JProperty("Name", "John Smith"),
   new JProperty("BirthDate", new DateTime(1983, 3, 20))
);

JsonSerializer serializer = new JsonSerializer();
Person p = (Person)serializer.Deserialize(new JTokenReader(o), typeof(Person));

Console.WriteLine(p.Name);

The class definition for Person should be compatible to the following:

class Person {
    public string Name { get; internal set; }
    public DateTime BirthDate { get; internal set; }
}

Edit

If you are using a recent version of JSON.net and don't need custom serialization, please see TienDo's answer above (or below if you upvote me :P ), which is more concise.

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