Why is there not a `fieldof` or `methodof` operato

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Closed 2 years ago.

They could be used as follows:

FieldInfo field = fieldof(string.Empty);
MethodInfo method1 = methodof(int.ToString);
MethodInfo method2 = methodof(int.ToString(IFormatProvider));

fieldof could be compiled to IL as:

ldtoken <field>
call FieldInfo.GetFieldFromHandle

methodof could be compiled to IL as:

ldtoken <method>
call MethodBase.GetMethodFromHandle

Whenever the typeof operator is used, you get perfect Find All References results. Unfortunately, as soon as you go to fields or methods, you end up with nasty hacks. I think you could do the following... or you can go back to getting a field by name.

public static FieldInfo fieldof<T>(Expression<Func<T>> expression)
{
    MemberExpression body = (MemberExpression)expression.Body;
    return (FieldInfo)body.Member;
}

public static MethodInfo methodof<T>(Expression<Func<T>> expression)
{
    MethodCallExpression body = (MethodCallExpression)expression.Body;
    return body.Method;
}

public static MethodInfo methodof(Expression<Action> expression)
{
    MethodCallExpression body = (MethodCallExpression)expression.Body;
    return body.Method;
}

public static void Test()
{
    FieldInfo field = fieldof(() => string.Empty);
    MethodInfo method1 = methodof(() => default(string).ToString());
    MethodInfo method2 = methodof(() => default(string).ToString(default(IFormatProvider)));
    MethodInfo method3 = methodof(() => default(List<int>).Add(default(int)));
}

Answer 1

this is a generic type version, that can use F2 to rename and not need modify existed code in the example, the method name is GetPKValue

var typFactory = typeof(FormFieldFactory<>).MakeGenericType(entity.GetType());
var methodName = new Func<object, object>(FormFieldFactory<object>.GetPKValue).Method.Name;

var theMethod =
    (Func<object, object>)Delegate.CreateDelegate(
        typeof(Func<object, object>)
        , typFactory.GetMethod(methodName)
    );

Answer 2

You can actually avoid using both reflection and lambdas (.NET Framework 2.0). Consider the following class:

public class methodof<T>
{
    private MethodInfo method;

    public methodof(T func)
    {
        Delegate del = (Delegate)(object)func;
        this.method = del.Method;
    }

    public static implicit operator methodof<T>(T methodof)
    {
        return new methodof<T>(methodof);
    }

    public static implicit operator MethodInfo(methodof<T> methodof)
    {
        return methodof.method;
    }
}

and it's usage:

MethodInfo writeln = (methodof<Action>)Console.WriteLine;
MethodInfo parse = (methodof<Func<string, int>>)int.Parse;

Answer 3

Eric Lippert (on the C# design team) has an excellent overview/discussion on this topic here. To quote:

It’s an awesome feature that pretty much everyone involved in the design process wishes we could do, but there are good practical reasons why we choose not to. If there comes a day when designing it and implementing it is the best way we could spend our limited budget, we’ll do it. Until then, use Reflection.

Answer 4

@280Z28 - We were just sitting down to figure out how to do this when I found your question & code. We needed a PropertyOf method so I added it. Here it is in case anybody else needs it. Thx for the great question.

     public static PropertyInfo PropertyOf<T>(Expression<Func<T>> expression)
    {
        MemberExpression body = (MemberExpression)expression.Body;
        PropertyInfo pi = body.Member as PropertyInfo;
        if (pi != null)
        {
            return pi;
        }
        else throw new ArgumentException("Lambda must be a Property.");
    } 

      [TestMethod()]
    public void MethodofPropertyOfTest<T>()
    {

        string foo = "Jamming";
        MethodInfo method1 = ReflectionHelper.Methodof(() => default(string).ToString());
        PropertyInfo prop = ReflectionHelper.PropertyOf(() => default(string).Length);
        Assert.AreEqual(method1.Invoke(foo, null), "Jamming");
        Assert.AreEqual(prop.GetGetMethod().Invoke(foo, null), foo.Length);
    }