How can I fill a div with an image while keeping i

Question

I found this thread — How do you stretch an image to fill a <div> while keeping the image's aspect-ratio? — that is not entirely the thing that I want.

I have a div with a certain size and an image inside of it. I want to always fill-out the div with the image regardless if the image is landscape or portrait. And it doesn't matter if the image is cut-off (the div itself has overflow hidden).

So if the image is portrait I want the width to be 100% and the height:auto so it stays in proportion. If the image is landscape I want the height to be 100% and the width to beauto`. Sounds complicated right?

<div class="container">
   <img src="some-image.jpg" alt="Could be portrait or landscape"/>
</div>

Since I don't know how to do it I simply created a quick image of what I mean. I can't even properly describe it.

So, I guess I'm not the first one asking this. However I couldn't really find a solution to this. Maybe there is some new CSS3 way of doing this - I'm thinking of flex-box. Any idea? Maybe it's even easier than I expect it to be?

Answer 1

.image-wrapper{
    width: 100px;
    height: 100px;
    border: 1px solid #ddd;
}
.image-wrapper img {
    object-fit: contain;
    min-width: 100%;
    min-height: 100%;
    width: auto;
    height: auto;
    max-width: 100%;
    max-height: 100%;
}

<div class="image-wrapper">
  <img src="">
</div>

Answer 2

Try this:

img {
  position: relative;
  left: 50%;
  min-width: 100%;
  min-height: 100%;
  transform: translateX(-50%);
}

Hope this helps

Answer 3

You can use div to achieve this. without img tag :) hope this helps.

.img{
	width:100px;
	height:100px;
	background-image:url('http://www.mandalas.com/mandala/htdocs/images/Lrg_image_Pages/Flowers/Large_Orange_Lotus_8.jpg');
	background-repeat:no-repeat;
	background-position:center center;
	border:1px solid red;
	background-size:cover;
}
.img1{
	width:100px;
	height:100px;
	background-image:url('https://images.freeimages.com/images/large-previews/9a4/large-pumpkin-1387927.jpg');
	background-repeat:no-repeat;
	background-position:center center;
	border:1px solid red;
	background-size:cover;
}

<div class="img">	
</div>
<div class="img1">	
</div>

Answer 4

The only way I achieved the "best case" scenario described, was putting the image as a background:

<div class="container"></div>​

.container {
    width: 150px;
    height: 100px;
    background-image: url("http://i.stack.imgur.com/2OrtT.jpg");
    background-size: cover;
    background-repeat: no-repeat;
    background-position: 50% 50%;
}​

Answer 5

It's a bit late but I just had the same problem and finally solved it with the help of another stackoverflow post (https://stackoverflow.com/a/29103071).

.img {
   object-fit: cover;
   width: 50px;
   height: 100px;
}

Hope this still helps somebody.

Ps: Also works together with max-height, max-width, min-width and min-height css properties. It's espacially handy with using lenght units like 100% or 100vh/100vw to fill the container or the whole browser window.

Answer 6

Consider using background-size: cover (IE9+) in conjunction with background-image. For IE8-, there is a polyfill.