How do I find an array item with TypeScript? (a mo

2020-01-25 06:54发布

Is there a canonical way to find an item in an array with TypeScript?

ES6+ allows this simple/clean approach

[{"id":1}, {"id":-2}, {"id":3}].find(myObj => myObj.id < 0)  // returns {"id":-2}

TypeScript implements many ES6+ features and continues to do so. It seems likely it has at least as nice a solution, so:

How can an item be found in a array using TypeScript, considering ease of use, modern best practices, and elegance via simplicity?
(restating the question slightly to seek best approaches)

Notes

  • "item" could be a JavaScript object, or almost anything else. The example above happens to be to find plain ol' native JS objects, but many scenarios exist.

  • "canonical" is just a fancy way in Computer Science (and other fields) to say "general accepted rule or standard formula" (remember everyone here didn't know that at some point)

  • This is not about new features. Any version of JS could do this. However the form to do so gets less and less appealing the farther you go back in time.

  • TypeScript roadmap for reference.

标签: typescript
5条回答
▲ chillily
2楼-- · 2020-01-25 07:10

If you need some es6 improvements not supported by Typescript, you can target es6 in your tsconfig and use Babel to convert your files in es5.

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聊天终结者
3楼-- · 2020-01-25 07:17

Part One - Polyfill

For browsers that haven't implemented it, a polyfill for array.find. Courtesy of MDN.

if (!Array.prototype.find) {
  Array.prototype.find = function(predicate) {
    if (this == null) {
      throw new TypeError('Array.prototype.find called on null or undefined');
    }
    if (typeof predicate !== 'function') {
      throw new TypeError('predicate must be a function');
    }
    var list = Object(this);
    var length = list.length >>> 0;
    var thisArg = arguments[1];
    var value;

    for (var i = 0; i < length; i++) {
      value = list[i];
      if (predicate.call(thisArg, value, i, list)) {
        return value;
      }
    }
    return undefined;
  };
}

Part Two - Interface

You need to extend the open Array interface to include the find method.

interface Array<T> {
    find(predicate: (search: T) => boolean) : T;
}

When this arrives in TypeScript, you'll get a warning from the compiler that will remind you to delete this.

Part Three - Use it

The variable x will have the expected type... { id: number }

var x = [{ "id": 1 }, { "id": -2 }, { "id": 3 }].find(myObj => myObj.id < 0);
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甜甜的少女心
4楼-- · 2020-01-25 07:17

For some projects it's easier to set your target to es6 in your tsconfig.json.

{
  "compilerOptions": {
    "target": "es6",
    ...
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beautiful°
5楼-- · 2020-01-25 07:17

Playing with the tsconfig.json You can also targeting es5 like this :

{
    "compilerOptions": {
        "experimentalDecorators": true,
        "module": "commonjs", 
        "target": "es5"
    }
    ...
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爱情/是我丢掉的垃圾
6楼-- · 2020-01-25 07:28

You could just use underscore library.

Install it:

   npm install underscore --save
   npm install @types/underscore --save-dev

Import it

   import _ = require('underscore');

Use it

    var x = _.filter(
      [{ "id": 1 }, { "id": -2 }, { "id": 3 }],
      myObj => myObj.id < 0)
    );
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