How do I check if an object's type is a partic

2020-01-25 05:35发布

I was thinking along the lines of using typeid() but I don't know how to ask if that type is a subclass of another class (which, by the way, is abstract)

11条回答
小情绪 Triste *
2楼-- · 2020-01-25 06:36

You really shouldn't. If your program needs to know what class an object is, that usually indicates a design flaw. See if you can get the behavior you want using virtual functions. Also, more information about what you are trying to do would help.

I am assuming you have a situation like this:

class Base;
class A : public Base {...};
class B : public Base {...};

void foo(Base *p)
{
  if(/* p is A */) /* do X */
  else /* do Y */
}

If this is what you have, then try to do something like this:

class Base
{
  virtual void bar() = 0;
};

class A : public Base
{
  void bar() {/* do X */}
};

class B : public Base
{
  void bar() {/* do Y */}
};

void foo(Base *p)
{
  p->bar();
}

Edit: Since the debate about this answer still goes on after so many years, I thought I should throw in some references. If you have a pointer or reference to a base class, and your code needs to know the derived class of the object, then it violates Liskov substitution principle. Uncle Bob calls this an "anathema to Object Oriented Design".

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地球回转人心会变
3楼-- · 2020-01-25 06:36

In c# you can simply say:

if (myObj is Car) {

}
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唯我独甜
4楼-- · 2020-01-25 06:38

 

class Base
{
  public: virtual ~Base() {}
};

class D1: public Base {};

class D2: public Base {};

int main(int argc,char* argv[]);
{
  D1   d1;
  D2   d2;

  Base*  x = (argc > 2)?&d1:&d2;

  if (dynamic_cast<D2*>(x) == nullptr)
  {
    std::cout << "NOT A D2" << std::endl;
  }
  if (dynamic_cast<D1*>(x) == nullptr)
  {
    std::cout << "NOT A D1" << std::endl;
  }
}
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疯言疯语
5楼-- · 2020-01-25 06:38

You can do it with dynamic_cast (at least for polymorphic types).

Actually, on second thought--you can't tell if it is SPECIFICALLY a particular type with dynamic_cast--but you can tell if it is that type or any subclass thereof.

template <class DstType, class SrcType>
bool IsType(const SrcType* src)
{
  return dynamic_cast<const DstType*>(src) != nullptr;
}
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Viruses.
6楼-- · 2020-01-25 06:39

I was thinking along the lines of using typeid()...

Well, yes, it could be done by comparing: typeid().name(). If we take the already described situation, where:

class Base;
class A : public Base {...};
class B : public Base {...};

void foo(Base *p)
{
  if(/* p is A */) /* do X */
  else /* do Y */
}

A possible implementation of foo(Base *p) would be:

#include <typeinfo>

void foo(Base *p)
{
    if(typeid(*p) == typeid(A))
    {
        // the pointer is pointing to the derived class A
    }  
    else if (typeid(*p).name() == typeid(B).name()) 
    {
        // the pointer is pointing to the derived class B
    }
}
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