I am working on Bluetooth low energy concept project. I am getting the RSSI value between 1 and 100. As I move the tag the RSSI value increase as the peripheral moves away from the iPhone and decreases as it moves closer.
Can anybody help me to get exact distance between the iPhone and the Bluetooth tag based on the RSSI value? Are there any available formulas?
I am getting the RSSI value of the device with the help of this bluetooth Low energy delegate method:
- (void)centralManager:(CBCentralManager *)central didDiscoverPeripheral:(CBPeripheral
*)peripheral advertisementData:(NSDictionary *)advertisementData RSSI:(NSNumber *)RSSI
In swift 4.2
More detailed answer Here
Finding distance from RSSI is bit tricky and it depends on lots of factors, even test environment and antenna orientation etc. Following paper is having some study regarding the same http://www.s2is.org/Issues/v1/n2/papers/paper14.pdf
I answered this in another thread, repeating it here.
In line-of-sight (no obstacles causing change in RSSI), -6dB seems to be double the distance.
You can not get an exact position, only a circular maximum distance.
Using triangulation with 2-3 or more devices you get a much more accurate positioning result. You can get this purely from Advertisement packages but you must either Disable scan -> Enable scan or tell iOS CoreBluetooth to report all adv packages.
In foreground mode you can do this but in background mode you can't get all adv packages. You must connect and read RSSI to do it in the background.
There are quite a number of RSSI-based localization techniques like triangulation and fingerprinting. None of them are perfect. RSSI is affected by many factors like obstacles, multipath fading, antenna polarization and cross-body shielding.
The theoretical relationship between RSSI and distance is something like this:
where d is the distance and A is the offset which is the measured RSSI 1 meter point away from the BLE device.
Simply google for
RSSI[dbm] = −(10n log10(d) − A)
and you will find some sources about it.