How do I round a number in JavaScript?

2020-01-24 11:49发布

While working on a project, I came across a JS-script created by a former employee that basically creates a report in the form of

Name : Value
Name2 : Value2

etc.

The peoblem is that the values can sometimes be floats (with different precision), integers, or even in the form 2.20011E+17. What I want to output are pure integers. I don't know a lot of JavaScript, though. How would I go about writing a method that takes these sometimes-floats and makes them integers?

8条回答
放荡不羁爱自由
2楼-- · 2020-01-24 12:05

You can use Math.round() for rounding numbers to the nearest integer.

Math.round(532.24) => 532

Also, you can use parseInt() and parseFloat() to cast a variable to a certain type, in this case integer and floating point.

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Explosion°爆炸
3楼-- · 2020-01-24 12:06

Math.floor(19.5) = 19 should also work.

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ゆ 、 Hurt°
4楼-- · 2020-01-24 12:08

You hav to convert your input into a number and then round them:

function toInteger(number){ 
  return Math.round(  // round to nearest integer
    Number(number)    // type cast your input
  ); 
};

Or as a one liner:

function toInt(n){ return Math.round(Number(n)); };

Testing with different values:

toInteger(2.5);           // 3
toInteger(1000);          // 1000
toInteger("12345.12345"); // 12345
toInteger("2.20011E+17"); // 220011000000000000
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看我几分像从前
5楼-- · 2020-01-24 12:10

A very good approximation for rounding:

function Rounding (number, precision){

var newNumber;
var sNumber = number.toString();

var increase = precision + sNumber.length - sNumber.indexOf('.') + 1;

if (number < 0)
  newNumber = (number -  5 * Math.pow(10,-increase));
else
  newNumber = (number +  5 * Math.pow(10,-increase));

var multiple = Math.pow(10,precision);

return Math.round(newNumber * multiple)/multiple;
}

Only in some cases when the length of the decimal part of the number is very long will it be incorrect.

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家丑人穷心不美
6楼-- · 2020-01-24 12:11

Here is a way to be able to use Math.round() with a second argument (number of decimals for rounding):

// 'improve' Math.round() to support a second argument
var _round = Math.round;
Math.round = function(number, decimals /* optional, default 0 */)
{
  if (arguments.length == 1)
    return _round(number);

  var multiplier = Math.pow(10, decimals);
  return _round(number * multiplier) / multiplier;
}

// examples
Math.round('123.4567', 2); // => 123.46
Math.round('123.4567');    // => 123
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等我变得足够好
7楼-- · 2020-01-24 12:13

According to the ECMAScript specification, numbers in JavaScript are represented only by the double-precision 64-bit format IEEE 754. Hence there is not really an integer type in JavaScript.

Regarding the rounding of these numbers, there are a number of ways you can achieve this. The Math object gives us three rounding methods wich we can use:

The Math.round() is most commonly used, it returns the value rounded to the nearest integer. Then there is the Math.floor() wich returns the largest integer less than or equal to a number. Lastly we have the Math.ceil() function that returns the smallest integer greater than or equal to a number.

There is also the toFixed() that returns a string representing the number using fixed-point notation.

Ps.: There is no 2nd argument in the Math.round() method. The toFixed() is not IE specific, its within the ECMAScript specification aswell

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