How to extract base URL from a string in JavaScrip

Question

I'm trying to find a relatively easy and reliable method to extract the base URL from a string variable using JavaScript (or jQuery).

For example, given something like:

http://www.sitename.com/article/2009/09/14/this-is-an-article/

I'd like to get:

http://www.sitename.com/

Is a regular expression the best bet? If so, what statement could I use to assign the base URL extracted from a given string to a new variable?

I've done some searching on this, but everything I find in the JavaScript world seems to revolve around gathering this information from the actual document URL using location.host or similar.

Answer 1

This works:

location.href.split(location.pathname)[0];

Answer 2

To get the origin of any url, including paths within a website (/my/path) or schemaless (//example.com/my/path), or full (http://example.com/my/path) I put together a quick function.

In the snippet below, all three calls should log https://stacksnippets.net.

function getOrigin(url)
{
  if(/^\/\//.test(url))
  { // no scheme, use current scheme, extract domain
    url = window.location.protocol + url;
  }
  else if(/^\//.test(url))
  { // just path, use whole origin
    url = window.location.origin + url;
  }
  return url.match(/^([^/]+\/\/[^/]+)/)[0];
}

console.log(getOrigin('https://stacksnippets.net/my/path'));
console.log(getOrigin('//stacksnippets.net/my/path'));
console.log(getOrigin('/my/path'));

Answer 3

A good way is to use JavaScript native api URL object. This provides many usefull url parts.

For example:

const url = 'https://stackoverflow.com/questions/1420881/how-to-extract-base-url-from-a-string-in-javascript'

const urlObject = new URL(url);

console.log(urlObject);


// RESULT: 
//________________________________
hash: "",
host: "stackoverflow.com",
hostname: "stackoverflow.com",
href: "https://stackoverflow.com/questions/1420881/how-to-extract-base-url-from-a-string-in-javascript",
origin: "https://stackoverflow.com",
password: "",
pathname: "/questions/1420881/how-to-extract-base-url-from-a-string-in-javaript",
port: "",
protocol: "https:",
search: "",
searchParams: [object URLSearchParams]
... + some other methods

As you can see here you can just access whatever you need.

For example: console.log(urlObject.host); // "stackoverflow.com"

doc for URL

Answer 4

You can use below codes for get different parameters of Current URL

alert("document.URL : "+document.URL);
alert("document.location.href : "+document.location.href);
alert("document.location.origin : "+document.location.origin);
alert("document.location.hostname : "+document.location.hostname);
alert("document.location.host : "+document.location.host);
alert("document.location.pathname : "+document.location.pathname);

Answer 5

function getBaseURL() {
    var url = location.href;  // entire url including querystring - also: window.location.href;
    var baseURL = url.substring(0, url.indexOf('/', 14));


    if (baseURL.indexOf('http://localhost') != -1) {
        // Base Url for localhost
        var url = location.href;  // window.location.href;
        var pathname = location.pathname;  // window.location.pathname;
        var index1 = url.indexOf(pathname);
        var index2 = url.indexOf("/", index1 + 1);
        var baseLocalUrl = url.substr(0, index2);

        return baseLocalUrl + "/";
    }
    else {
        // Root Url for domain name
        return baseURL + "/";
    }

}

You then can use it like this...

var str = 'http://en.wikipedia.org/wiki/Knopf?q=1&t=2';
var url = str.toUrl();

The value of url will be...

{
"original":"http://en.wikipedia.org/wiki/Knopf?q=1&t=2",<br/>"protocol":"http:",
"domain":"wikipedia.org",<br/>"host":"en.wikipedia.org",<br/>"relativePath":"wiki"
}

The "var url" also contains two methods.

var paramQ = url.getParameter('q');

In this case the value of paramQ will be 1.

var allParameters = url.getParameters();

The value of allParameters will be the parameter names only.

["q","t"]

Tested on IE,chrome and firefox.

Answer 6

You can do it using a regex :

/(http:\/\/)?(www)[^\/]+\//i

does it fit ?