Print series of prime numbers in python

Question

I am trying to learn Python programming, and I'm pretty new at this.

I was having issues in printing a series of prime numbers from one to hundred. I can't figure our what's wrong with my code.

Here's what I wrote; it prints all the odd numbers instead of primes:

for num in range(1,101):
    for i in range(2,num):
        if (num%i==0):
            break
        else:
            print(num)
            break

Answer 1

I was inspired by Igor and made a code block that creates a list:

def prime_number():

for num in range(2, 101):
    prime = True
    for i in range(2, num):
        if (num % i == 0):
            prime = False
    if prime and num not in num_list:
        num_list.append(num)
    else:
        pass
return num_list


num_list = []
prime_number()
print(num_list)

Answer 2

we can make a list of prime numbers using sympy library

import sympy
lower=int(input("lower value:"))          #let it be 30
upper=int(input("upper value:"))          #let it be 60
l=list(sympy.primerange(lower,upper+1))   #[31,37,41,43,47,53,59]
print(l)

Answer 3

n = int(raw_input('Enter the integer range to find prime no :'))
p = 2
while p<n:
  i = p
  cnt = 0
  while i>1:
    if p%i == 0:
        cnt+=1
    i-=1
  if cnt == 1:
     print "%s is Prime Number"%p
  else:
     print "%s is Not Prime Number"%p
  p+=1

Answer 4

for num in range(1,101):
    prime = True
    for i in range(2,num/2):
        if (num%i==0):
            prime = False
    if prime:
       print num

Answer 5

n = int(input())
is_prime = lambda n: all( n%i != 0 for i in range(2, int(n**.5)+1) )
def Prime_series(n):
    for i in range(2,n):
        if is_prime(i) == True:
            print(i,end = " ")
        else:
            pass
Prime_series(n)

Here is a simplified answer using lambda function.

Answer 6

Here is a different approach that trades space for faster search time. This may be fastest so.

import math

def primes(n):
    if n < 2:
        return []
    numbers = [0]*(n+1)
    primes = [2]
    # Mark all odd numbers as maybe prime, leave evens marked composite.
    for i in xrange(3, n+1, 2):
        numbers[i] = 1

    sqn = int(math.sqrt(n))
    # Starting with 3, look at each odd number.
    for i in xrange(3, len(numbers), 2):
        # Skip if composite.
        if numbers[i] == 0:
            continue
        # Number is prime.  Would have been marked as composite if there were
        # any smaller prime factors already examined.
        primes.append(i)
        if i > sqn:
            # All remaining odd numbers not marked composite must be prime.
            primes.extend([i for i in xrange(i+2, len(numbers), 2)
                           if numbers[i]])
            break
        # Mark all multiples of the prime as composite.  Check odd multiples.
        for r in xrange(i*i, len(numbers), i*2):
            numbers[r] = 0

    return primes

n = 1000000
p = primes(n)
print "Found", len(p), "primes <=", n