I try to read-in 2 values using scanf() in C, but the values the system writes into memory are not equal to my entered values. Here is the code:
double a,b;
printf("--------\n"); //seperate lines
scanf("%ld",&a);
printf("--------\n");
scanf("%ld",&b);
printf("%d %d",a,b);
If I enter 1 and 2, CMD returns a correct, but b = -858993460 Here is what I already tried: using float or int instead of double, using scanf_s, using scanf("%d or %f for %i or %li or %lf or %e or %g ), using fflush(stdin) to clear keyboard buffer, reading in b first, trying like all possible combinations. I found out that there is a problem with the length of double on 32 bit OS, so that you are forced to use scanf("%lf", &f) to read in a double. No matter what I do, second value is always wrong.
I use MS VS express 2012 for Desktop on Windows 7 32 bit OS.
As far as i know
%d
means decadic which is number without decimal point. if you want to load double value, use%lf
conversion (long float). for printf your values are wrong for same reason,%d
is used only for integer (and possibly chars if you know what you are doing) numbers.Example:
Use the
%lf
format specifier to read a double:Wikipedia has a decent reference for available format specifiers.
You'll need to use the
%lf
format specifier to print out the results as well:You are using wrong formatting sequence for
double
, you should use%lf
instead of%ld
:Format specifier in
printf
should be%f
fordoubl
datatypes sincefloat
datatyles eventually convert todouble
datatypes insideprintf
.There is no provision to print
float
data. Please find the discussion here : Correct format specifier for double in printfUsing
%lf
will help you in solving this problem.Use :