Weird Try-Except-Else-Finally behavior with Return

Question

This is some code that is behaving peculiarly. This is a simplified version of the behavior that I've written. This will still demonstrate the weird behavior and I had some specific questions on why this is occurring.

I'm using Python 2.6.6 on Windows 7.

def demo1():
    try:
        raise RuntimeError,"To Force Issue"
    except:
        return 1
    else:
        return 2
    finally:
        return 3

def demo2():
    try:
        try:
            raise RuntimeError,"To Force Issue"
        except:
            return 1
        else:
            return 2
        finally:
            return 3
    except:
        print 4
    else:
        print 5
    finally:
        print 6

Results:

>>> print demo1()
3
>>> print demo2()
6
3

• Why is demo one returning 3 instead of 1?
• Why is demo two printing 6 instead of printing 6 w/ 4 or 5?

Answer 1

The execution order is:

1. try block all completes normally -> finally block -> function ends
2. try block run and get into exception A -> finally block -> function ends
3. try block make a return value and call return -> finally block -> popup return value -> function ends

So, any return in the finally block will end the steps in advance.

Answer 2

Because finally statements are guaranteed to be executed (well, presuming no power outage or anything outside of Python's control). This means that before the function can return, it must run the finally block, which returns a different value.

The Python docs state:

When a return, break or continue statement is executed in the try suite of a try…finally statement, the finally clause is also executed ‘on the way out.’

The return value of a function is determined by the last return statement executed. Since the finally clause always executes, a return statement executed in the finally clause will always be the last one executed:

This means that when you try to return, the finally block is called, returning it's value, rather than the one that you would have had.