Parsing JSON array into java.util.List with Gson

2020-01-23 06:10发布

I have a JsonObject named "mapping" with the following content:

{
    "client": "127.0.0.1",
    "servers": [
        "8.8.8.8",
        "8.8.4.4",
        "156.154.70.1",
        "156.154.71.1"
    ]
}

I know I can get the array "servers" with:

mapping.get("servers").getAsJsonArray()

And now I want to parse that JsonArray into a java.util.List...

What is the easiest way to do this?

5条回答
家丑人穷心不美
2楼-- · 2020-01-23 06:38

I read solution from official website of Gson at here

And this code for you:

    String json = "{"client":"127.0.0.1","servers":["8.8.8.8","8.8.4.4","156.154.70.1","156.154.71.1"]}";

    JsonObject jsonObject = new Gson().fromJson(json, JsonObject.class);
    JsonArray jsonArray = jsonObject.getAsJsonArray("servers");

    String[] arrName = new Gson().fromJson(jsonArray, String[].class);

    List<String> lstName = new ArrayList<>();
    lstName = Arrays.asList(arrName);

    for (String str : lstName) {
        System.out.println(str);
    }    

Result show on monitor:

8.8.8.8
8.8.4.4
156.154.70.1
156.154.71.1
查看更多
相关推荐>>
3楼-- · 2020-01-23 06:43

Given you start with mapping.get("servers").getAsJsonArray(), if you have access to Guava Streams, you can do the below one-liner:

List<String> servers = Streams.stream(jsonArray.iterator())
                              .map(je -> je.getAsString())
                              .collect(Collectors.toList());

Note StreamSupport won't be able to work on JsonElement type, so it is insufficient.

查看更多
干净又极端
4楼-- · 2020-01-23 06:49

Below code is using com.google.gson.JsonArray. I have printed the number of element in list as well as the elements in List

import java.util.ArrayList;

import com.google.gson.Gson;
import com.google.gson.JsonArray;
import com.google.gson.JsonObject;
import com.google.gson.JsonParser;


public class Test {

    static String str = "{ "+ 
            "\"client\":\"127.0.0.1\"," + 
            "\"servers\":[" + 
            "    \"8.8.8.8\"," + 
            "    \"8.8.4.4\"," + 
            "    \"156.154.70.1\"," + 
            "    \"156.154.71.1\" " + 
            "    ]" + 
            "}";

    public static void main(String[] args) {
        // TODO Auto-generated method stub
        try {

            JsonParser jsonParser = new JsonParser();
            JsonObject jo = (JsonObject)jsonParser.parse(str);
            JsonArray jsonArr = jo.getAsJsonArray("servers");
            //jsonArr.
            Gson googleJson = new Gson();
            ArrayList jsonObjList = googleJson.fromJson(jsonArr, ArrayList.class);
            System.out.println("List size is : "+jsonObjList.size());
                    System.out.println("List Elements are  : "+jsonObjList.toString());


        } catch (Exception e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }
    }

}

OUTPUT

List size is : 4

List Elements are  : [8.8.8.8, 8.8.4.4, 156.154.70.1, 156.154.71.1]
查看更多
Explosion°爆炸
5楼-- · 2020-01-23 06:59

I was able to get the list mapping to work with just using @SerializedName for all fields.. no logic around Type was necessary.

Running the code - in step #4 below - through the debugger, I am able to observe that the List<ContentImage> mGalleryImages object populated with the JSON data

Here's an example:

1. The JSON

   {
    "name": "Some House",
    "gallery": [
      {
        "description": "Nice 300sqft. den.jpg",
        "photo_url": "image/den.jpg"
      },
      {
        "description": "Floor Plan",
        "photo_url": "image/floor_plan.jpg"
      }
    ]
  }

2. Java class with the List

public class FocusArea {

    @SerializedName("name")
    private String mName;

    @SerializedName("gallery")
    private List<ContentImage> mGalleryImages;
}

3. Java class for the List items

public class ContentImage {

    @SerializedName("description")
    private String mDescription;

    @SerializedName("photo_url")
    private String mPhotoUrl;

    // getters/setters ..
}

4. The Java code that processes the JSON

    for (String key : focusAreaKeys) {

        JsonElement sectionElement = sectionsJsonObject.get(key);
        FocusArea focusArea = gson.fromJson(sectionElement, FocusArea.class);
    }
查看更多
Summer. ? 凉城
6楼-- · 2020-01-23 07:00

Definitely the easiest way to do that is using Gson's default parsing function fromJson().

There is an implementation of this function suitable for when you need to deserialize into any ParameterizedType (e.g., any List), which is fromJson(JsonElement json, Type typeOfT).

In your case, you just need to get the Type of a List<String> and then parse the JSON array into that Type, like this:

import java.lang.reflect.Type;
import com.google.gson.reflect.TypeToken;

JsonElement yourJson = mapping.get("servers");
Type listType = new TypeToken<List<String>>() {}.getType();

List<String> yourList = new Gson().fromJson(yourJson, listType);

In your case yourJson is a JsonElement, but it could also be a String, any Reader or a JsonReader.

You may want to take a look at Gson API documentation.

查看更多
登录 后发表回答