String formatting in Python

2020-01-22 13:35发布

I want to do something like String.Format("[{0}, {1}, {2}]", 1, 2, 3) which returns:

[1, 2, 3]

How do I do this in Python?

10条回答
贪生不怕死
2楼-- · 2020-01-22 13:54

If you don't know how many items are in list, this aproach is the most universal

>>> '[{0}]'.format(', '.join([str(i) for i in [1,2,3]]))

'[1, 2, 3]'

It is mouch simplier for list of strings

>>> '[{0}]'.format(', '.join(['a','b','c']))
'[a, b, c]'
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闹够了就滚
3楼-- · 2020-01-22 13:59

The previous answers have used % formatting, which is being phased out in Python 3.0+. Assuming you're using Python 2.6+, a more future-proof formatting system is described here:

http://docs.python.org/library/string.html#formatstrings

Although there are more advanced features as well, the simplest form ends up looking very close to what you wrote:

>>> "[{0}, {1}, {2}]".format(1, 2, 3)
[1, 2, 3]
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Juvenile、少年°
4楼-- · 2020-01-22 14:01

To print elements sequentially use {} without specifying the index

print('[{},{},{}]'.format(1,2,3))

(works since python 2.7 and python 3.1)

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仙女界的扛把子
5楼-- · 2020-01-22 14:01

PEP 498 which landed in python 3.6 added literal string interpolation, which is basically a shortened form of format.

You can now do:

f"[{1}, {2}, {3}]"

Common other uses I find useful are:

pi = 3.141592653589793
today = datetime(year=2018, month=2, day=3)

num_2 = 2     # Drop assigned values in
num_3 = "3"   # Call repr(), or it's shortened form !r
padding = 5   # Control prefix padding
precision = 3 #   and precision for printing


f"""[{1},
     {num_2},
     {num_3!r},
     {pi:{padding}.{precision}},
     {today:%B %d, %Y}]"""

Which will produce:

"[1,\n     2,\n     '3',\n      3.14,\n     February 03, 2018]"
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戒情不戒烟
6楼-- · 2020-01-22 14:05

Very short answer.

example: print("{:05.2f}".format(2.5163)) returns 02.51

  • {} Set here Variable
  • : Start Styling
  • 0 leading with zeroes, " " leading with whitespaces
  • 5 LENGTH OF FULL STRING (Point counts, 00.00 is len 5 not 4)
  • .2 two digit after point, with rounding.
  • f for floats
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Rolldiameter
7楼-- · 2020-01-22 14:10

You can do it three ways:


Use Python's automatic pretty printing:

print [1, 2, 3]   # Prints [1, 2, 3]

Showing the same thing with a variable:

numberList = [1, 2]
numberList.append(3)
print numberList   # Prints [1, 2, 3]

Use 'classic' string substitutions (ala C's printf). Note the different meanings here of % as the string-format specifier, and the % to apply the list (actually a tuple) to the formatting string. (And note the % is used as the modulo(remainder) operator for arithmetic expressions.)

print "[%i, %i, %i]" % (1, 2, 3)

Note if we use our pre-defined variable, we'll need to turn it into a tuple to do this:

print "[%i, %i, %i]" % tuple(numberList)

Use Python 3 string formatting. This is still available in earlier versions (from 2.6), but is the 'new' way of doing it in Py 3. Note you can either use positional (ordinal) arguments, or named arguments (for the heck of it I've put them in reverse order.

print "[{0}, {1}, {2}]".format(1, 2, 3)

Note the names 'one' ,'two' and 'three' can be whatever makes sense.)

print "[{one}, {two}, {three}]".format(three=3, two=2, one=1)
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