Generating a range of numbers in MySQL

Question

How do I generate a range of consecutive numbers (one per line) from a MySQL query so that I can insert them into a table?

For example:

nr
1
2
3
4
5

I would like to use only MySQL for this (not PHP or other languages).

Answer 1

Let's say you want to insert numbers 1 through 100 into your table. As long as you have some other table that has at least that many rows (doesn't matter the content of the table), then this is my preferred method:

INSERT INTO pivot100 
SELECT @ROW := @ROW + 1 AS ROW
 FROM someOtherTable t
 join (SELECT @ROW := 0) t2
 LIMIT 100
;

Want a range that starts with something other than 1? Just change what @ROW gets set to on the join.

Answer 2

Here is one way to do it set-based without loops. This can also be made into a view for re-use. The example shows the generation of a sequence from 0 through 999, but of course, it may be modified to suit.

INSERT INTO
    myTable
    (
    nr
    )
SELECT
    SEQ.SeqValue
FROM
(
SELECT
    (HUNDREDS.SeqValue + TENS.SeqValue + ONES.SeqValue) SeqValue
FROM
    (
    SELECT 0  SeqValue
    UNION ALL
    SELECT 1 SeqValue
    UNION ALL
    SELECT 2 SeqValue
    UNION ALL
    SELECT 3 SeqValue
    UNION ALL
    SELECT 4 SeqValue
    UNION ALL
    SELECT 5 SeqValue
    UNION ALL
    SELECT 6 SeqValue
    UNION ALL
    SELECT 7 SeqValue
    UNION ALL
    SELECT 8 SeqValue
    UNION ALL
    SELECT 9 SeqValue
    ) ONES
CROSS JOIN
    (
    SELECT 0 SeqValue
    UNION ALL
    SELECT 10 SeqValue
    UNION ALL
    SELECT 20 SeqValue
    UNION ALL
    SELECT 30 SeqValue
    UNION ALL
    SELECT 40 SeqValue
    UNION ALL
    SELECT 50 SeqValue
    UNION ALL
    SELECT 60 SeqValue
    UNION ALL
    SELECT 70 SeqValue
    UNION ALL
    SELECT 80 SeqValue
    UNION ALL
    SELECT 90 SeqValue
    ) TENS
CROSS JOIN
    (
    SELECT 0 SeqValue
    UNION ALL
    SELECT 100 SeqValue
    UNION ALL
    SELECT 200 SeqValue
    UNION ALL
    SELECT 300 SeqValue
    UNION ALL
    SELECT 400 SeqValue
    UNION ALL
    SELECT 500 SeqValue
    UNION ALL
    SELECT 600 SeqValue
    UNION ALL
    SELECT 700 SeqValue
    UNION ALL
    SELECT 800 SeqValue
    UNION ALL
    SELECT 900 SeqValue
    ) HUNDREDS
) SEQ

Answer 3

As you all understand, this is rather hacky so use with care

SELECT id % 12 + 1 as one_to_twelve FROM any_large_table group by one_to_twelve

Answer 4

DECLARE i INT DEFAULT 0;

WHILE i < 6 DO
  /* insert into table... */
  SET i = i + 1;
END WHILE;

Answer 5

Here's a hardware engineer's version of Pittsburgh DBA's solution:

SELECT
    (TWO_1.SeqValue + TWO_2.SeqValue + TWO_4.SeqValue + TWO_8.SeqValue + TWO_16.SeqValue) SeqValue
FROM
    (SELECT 0 SeqValue UNION ALL SELECT 1 SeqValue) TWO_1
    CROSS JOIN (SELECT 0 SeqValue UNION ALL SELECT 2 SeqValue) TWO_2
    CROSS JOIN (SELECT 0 SeqValue UNION ALL SELECT 4 SeqValue) TWO_4
    CROSS JOIN (SELECT 0 SeqValue UNION ALL SELECT 8 SeqValue) TWO_8
    CROSS JOIN (SELECT 0 SeqValue UNION ALL SELECT 16 SeqValue) TWO_16;

Answer 6

The idea I want to share is not a precise response for the question but can be useful for some so I would like to share it.

If you frequently need only a limited set of numbers then it can be beneficial to create a table with the numbers you may need and just use that table every time. For example:

CREATE TABLE _numbers (num int);
INSERT _numbers VALUES (0), (1), (2), (3), ...;

This can be applied only if you need numbers below a certain reasonable limit, so don't use it for generating sequence 1...1 million but can be used for numbers 1...10k, for example.

If you have this list of numbers in the _numbers table then you can write queries like this, for obtaining the individual characters of a string:

SELECT number, substr(name, num, 1) 
    FROM users
    JOIN _numbers ON num < length(name)
    WHERE user_id = 1234
    ORDER BY num;

If you need larger numbers than 10k then you can join the table to itself:

SELECT n1.num * 10000 + n2.num
    FROM _numbers n1
    JOIN _numbers n2
    WHERE n1 < 100 
    ORDER BY n1.num * 10000 + n2.num; -- or just ORDER BY 1 meaning the first column