Java skipping a line of code? VERY basic java [dup

Question

This question already has an answer here:

• Scanner is skipping nextLine() after using next() or nextFoo()? 15 answers

If you look at the line of code where it says

System.out.println("Please enter the firstname of your favourite female author");
mFirstName = scanner.nextLine();
System.out.println("Please enter her second name");
mSurname = scanner.nextLine();

It completely skips the firstname part and goes straight to surname? Any ideas why this is happenimh?

import java.util.*;
    'class university{
        public static void main(String[] args){
            Scanner scanner = new Scanner(System.in);
            Person2 mPerson, fPerson;

        String fFirstName, fSurname, mFirstName, mSurname;
        int fAge, mAge;

        System.out.println("Please enter the firstname of your favourite female author");
        fFirstName = scanner.nextLine();
        System.out.println("Please enter her second name");
        fSurname = scanner.nextLine();
        System.out.println("Please enter her age");
        fAge = scanner.nextInt();
         System.out.println("Please enter the firstname of your favourite female author");
         mFirstName = scanner.nextLine();
        System.out.println("Please enter her second name");
        mSurname = scanner.nextLine();
        System.out.println("Please enter her age");
        mAge = scanner.nextInt();
        System.out.print(fPerson);
    }
}

Answer 1

fAge = scanner.nextInt(); does not consume the line ending.

add scanner.nextLine() after that to absorb the end-of-line character and it will work.

Answer 2

Add a nextLine() call after you call nextInt(). Because nextInt() doesn't finish the line. So the next call to nextLine() will return an empty string.