Find all numbers in a string in Python 3 [duplicat

2019-09-21 08:59发布

Newbie here, been searching the net for hours for an answer.

string = "44-23+44*4522" # string could be longer

How do I make it a list, so the output is:

[44, 23, 44, 4522]

2条回答
男人必须洒脱
2楼-- · 2019-09-21 09:31

Using the regular expressions as suggested by AChampion, you can do the following.

string = "44-23+44*4522"
import re
result = re.findall(r'\d+',string)

The r'' signifies raw text, the '\d' find a decimal character and the + signifies 1 or more occurrences. If you expect floating points in your string that you don't want to be separated, you might what to bracket with a period '.'.

re.findall(r'[\d\.]+',string)
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狗以群分
3楼-- · 2019-09-21 09:37

Here you have your made up function, explained and detailed.
Since you're a newbie, this is a very simple approach so it can be easily understood.

def find_numbers(string):
    list = []
    actual = ""
    # For each character of the string
    for i in range(len(string)):
        # If is number
        if "0" <= string[i] <= "9":
            # Add number to actual list entry
            actual += string[i]
        # If not number and the list entry wasn't empty
        elif actual != "":
            list.append(actual);
            actual = "";
    # Check last entry
    if actual != "":
        list.append(actual);
    return list
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