Calculate difference between 2 date / times in Ora

Question

I have a table as follows:

Filename - varchar
Creation Date - Date format dd/mm/yyyy hh24:mi:ss
Oldest cdr date - Date format dd/mm/yyyy hh24:mi:ss

How can I calcuate the difference in hours minutes and seconds (and possibly days) between the two dates in Oracle SQL?

Thanks

Answer 1

(TO_DATE(:P_comapre_date_1, 'dd-mm-yyyy hh24:mi') - TO_DATE(:P_comapre_date_2, 'dd-mm-yyyy hh24:mi'))*60*60*24 sum_seconds,
         (TO_DATE(:P_comapre_date_1, 'dd-mm-yyyy hh24:mi') - TO_DATE(:P_comapre_date_2, 'dd-mm-yyyy hh24:mi'))*60*24 sum_minutes,
         (TO_DATE(:P_comapre_date_1, 'dd-mm-yyyy hh24:mi') - TO_DATE(:P_comapre_date_2, 'dd-mm-yyyy hh24:mi'))*24 sum_hours,
         (TO_DATE(:P_comapre_date_1, 'dd-mm-yyyy hh24:mi') - TO_DATE(:P_comapre_date_2, 'dd-mm-yyyy hh24:mi')) sum_days 

Answer 2

$sql="select bsp_bp,user_name,status,
to_char(ins_date,'dd/mm/yyyy hh12:mi:ss AM'),
to_char(pickup_date,'dd/mm/yyyy hh12:mi:ss AM'),
trunc((pickup_date-ins_date)*24*60*60,2),message,status_message 
from valid_bsp_req where id >= '$id'"; 

Answer 3

To get result in seconds:

select (END_DT - START_DT)*60*60*24 from MY_TABLE;

Check [https://community.oracle.com/thread/2145099?tstart=0][1]

Answer 4

You can substract dates in Oracle. This will give you the difference in days. Multiply by 24 to get hours, and so on.

SQL> select oldest - creation from my_table;

If your date is stored as character data, you have to convert it to a date type first.

SQL> select 24 * (to_date('2009-07-07 22:00', 'YYYY-MM-DD hh24:mi') 
             - to_date('2009-07-07 19:30', 'YYYY-MM-DD hh24:mi')) diff_hours 
       from dual;

DIFF_HOURS
----------
       2.5

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Note:

This answer applies to dates represented by the Oracle data type DATE. Oracle also has a data type TIMESTAMP, which can also represent a date (with time). If you subtract TIMESTAMP values, you get an INTERVAL; to extract numeric values, use the EXTRACT function.