Converting a string to a formatted date-time strin

2019-01-13 21:41发布

I'm trying to convert a string "20091229050936" into "05:09 29 December 2009 (UTC)"

>>>import time
>>>s = time.strptime("20091229050936", "%Y%m%d%H%M%S")
>>>print s.strftime('%H:%M %d %B %Y (UTC)')

gives AttributeError: 'time.struct_time' object has no attribute 'strftime'

Clearly, I've made a mistake: time is wrong, it's a datetime object! It's got a date and a time component!

>>>import datetime
>>>s = datetime.strptime("20091229050936", "%Y%m%d%H%M%S")

gives AttributeError: 'module' object has no attribute 'strptime'

How am I meant to convert a string into a formatted date-string?

5条回答
一纸荒年 Trace。
2楼-- · 2019-01-13 21:55

For datetime objects, strptime is a static method of the datetime class, not a free function in the datetime module:

>>> import datetime
>>> s = datetime.datetime.strptime("20091229050936", "%Y%m%d%H%M%S")
>>> print s.strftime('%H:%M %d %B %Y (UTC)')
05:09 29 December 2009 (UTC)
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成全新的幸福
3楼-- · 2019-01-13 21:59

time.strptime returns a time_struct; time.strftime accepts a time_struct as an optional parameter:

>>>s = time.strptime(page.editTime(), "%Y%m%d%H%M%S")
>>>print time.strftime('%H:%M %d %B %Y (UTC)', s)

gives 05:09 29 December 2009 (UTC)

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倾城 Initia
4楼-- · 2019-01-13 22:06

You can use easy_date to make it easy:

import date_converter
my_datetime = date_converter.string_to_string("20091229050936", "%Y%m%d%H%M%S", "%H:%M %d %B %Y (UTC)")
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闹够了就滚
5楼-- · 2019-01-13 22:12

For me this is the best and it works on Google App Engine as well

Example showing UTC-4

import datetime   
UTC_OFFSET = 4
local_datetime = datetime.datetime.now()
print (local_datetime - datetime.timedelta(hours=UTC_OFFSET)).strftime("%Y-%m-%d %H:%M:%S")
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混吃等死
6楼-- · 2019-01-13 22:16
from datetime import datetime
s = datetime.strptime("20091229050936", "%Y%m%d%H%M%S")
print("{:%H:%M %d %B %Y (UTC)}".format(s))
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