SQL query get count item for report per day of the

2019-09-20 00:21发布

i need sql query for report from table item per day(fix day1-day31 as column) of the month when i input month and year.

This is my table (item)

  ID   |   NAME  |   DATE
---------------------------------------------------
   1   |   ITEM A |   2015-2-25 13:37:49
   2   |   ITEM A |   2015-2-25 14:37:49
   3   |   ITEM A |   2015-2-26 13:30:55
   4   |   ITEM B |   2015-2-26 15:37:49
   5   |   ITEM B |   2015-2-26 17:57:49
   6   |   ITEM C |   2015-2-27 13:00:33


(input month=02 and year=2015)
What I need to achieve with a view is the following:

NAME | 1| 2| 3|…|25|26|27|28|29|30|31|Total
------------------------------------------------------
ITEM A| 0| 0| 0|…| 2 | 1 | 0 | 0 | 0 | 0 | 0 | 3
ITEM B| 0| 0| 0|…| 0 | 2 | 0 | 0 | 0 | 0 | 0 | 2
ITEM C| 0| 0| 0|…| 0 | 0 | 1 | 0 | 0 | 0 | 0 | 1


Any ideas would be very much appreciated.

Thanks in advance.

Sorry this is my first post.

3条回答
走好不送
2楼-- · 2019-09-20 00:32

This will do it for you. First test data:

CREATE TABLE data ([ID] int, [Name] varchar(30), [Date] datetime)

INSERT INTO data ([ID], [Name], [Date])
SELECT 1,'ITEM A','2015-2-25 13:37:49'
UNION ALL SELECT 2,'ITEM A','2015-2-25 14:37:49'
UNION ALL SELECT 3,'ITEM A','2015-2-26 13:30:55'
UNION ALL SELECT 4,'ITEM B','2015-2-26 15:37:49'
UNION ALL SELECT 5,'ITEM B','2015-2-26 17:57:49'
UNION ALL SELECT 6,'ITEM C','2015-2-27 13:00:33'

Then the query. Note you can use any data range, so if you want a full month just calculate that and put it in the @startDate and @endDate

DECLARE @startDate DATETIME='25-Feb-2015'
DECLARE @endDate DATETIME='28-Feb-2015'
DECLARE @numberOfDays INT = DATEDIFF(DAY, @startDate, @endDate)

declare @dayColumns TABLE (delta int, colName varchar(12))

-- Produce 1 row for each day in the report. Note that this is limited by the 
-- number of objects in sysobjects (which is about 2000 so its a high limit)
-- Each row contains a delta date offset, @startDate+delta gives each date to report 
-- which is converted to a valid SQL column name in the format colYYYYMMDD
INSERT INTO @dayColumns (delta, colName)
SELECT delta, 'col'+CONVERT(varchar(12),DATEADD(day,delta,@startDate),112) as colName from (
  select (ROW_NUMBER() OVER (ORDER BY sysobjects.id))-1 as delta FROM sysobjects 
) daysAhead
WHERE delta<=@numberOfDays

-- Create a comma seperated list of columns to report
DECLARE @cols AS NVARCHAR(MAX)= ''
SELECT @cols=CASE WHEN @cols='' THEN @cols ELSE @cols+',' END + colName FROM @dayColumns ORDER BY delta
DECLARE @totalCount AS NVARCHAR(MAX)= ''
SELECT @totalCount=CASE WHEN @totalCount='' THEN '' ELSE @totalCount+' + ' END + 'ISNULL(' + colName +',0)' FROM @dayColumns ORDER BY delta

-- Produce a SQL statement which outputs a variable number of pivoted columns
DECLARE @query AS NVARCHAR(MAX)
SELECT @query=
'declare @days TABLE (reportDay date, colName varchar(12))

INSERT INTO @days (reportDay, colName)
SELECT DATEADD(day,Delta,'''+CONVERT(varchar(22),@startDate,121)+'''), ''col''+CONVERT(varchar(12),DATEADD(day,delta,'''+CONVERT(varchar(22),@startDate,121)+'''),112) as colName from (
  select (ROW_NUMBER() OVER (ORDER BY sysobjects.id))-1 as Delta FROM sysobjects 
) daysAhead
WHERE Delta<='+CAST(@numberOfDays as varchar(10))+'

SELECT pivoted.*,'+@totalCount+' as total FROM (
  SELECT * FROM (
    select data.Name, d.colName, 1 as numRows
    from @days d
    LEFT OUTER JOIN data ON CAST(data.[Date] as DATE)=d.reportDay
  ) as s
  PIVOT (
    SUM(numRows) FOR colName in ('+@cols+')
  ) as pa
) as pivoted
WHERE Name is not null'

-- Run the query
EXEC (@query)

Output is:

    Name                           col20150225 col20150226 col20150227 col20150228 total
    ------------------------------ ----------- ----------- ----------- ----------- -----------
    ITEM A                         2           1           NULL        NULL        3
    ITEM B                         NULL        2           NULL        NULL        2
    ITEM C                         NULL        NULL        1           NULL        1

You can determine the date of each column by parsing the column header in your presentation code (it's format is colYYYYMMDD).

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来,给爷笑一个
3楼-- · 2019-09-20 00:33

You can do this using a PIVOT in your query

SELECT name, 
       [1], 
       [2], 
       [3], 
       [4], 
       [5],
       [6],
       [7],
       [8],
       [9],
       [10],
       [11],
       [12],
       [13],
       [14],
       [15],
       [16],
       [17],
       [18],
       [19], 
       [20], 
       [21], 
       [22], 
       [23], 
       [24], 
       [25], 
       [26], 
       [27], 
       [28], 
       [29], 
       [30], 
       [31],
       ([1] + [2] + [3] + [4] + [5] + [6] + [7] + [8] + [9] + [10] + [11] + [12] + [13] + [14] + [15] + [16] + [17] + [18] + [19] +  [20] + [21] + [22] + [23] + [24] + [25] + [26] + [27] + [28] + [29] + [30] + [31]) as total
FROM   
(
    SELECT Name, 
        id, 
        Datepart(day, [date]) day 
    FROM   item 
    WHERE  MONTH([date]) = 2 AND YEAR([date]) = 2015
) x 
PIVOT 
(
    count(id) 
    FOR day IN ([1], [2], [3], [4], [5], [6], [7], [8], [9], [10], [11], [12], [13], [14], [15], [16], [17], [18], [19],  [20], [21], [22], [23], [24], [25], [26], [27], [28], [29], [30], [31]) 
) p 
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女痞
4楼-- · 2019-09-20 00:36
select convert(varchar,PaymentDate,103) AS date,
       DatePart(MONTH,PaymentDate) as month,
       CAST(SUM(Total_Amount) as INT) as Revenue 
from Tbl_Name 
where YEAR(PaymentDate) = YEAR(CURRENT_TIMESTAMP)
  AND MONTH(PaymentDate) = MONTH(CURRENT_TIMESTAMP) 
GROUP BY convert(varchar,PaymentDate,103),
         DatePart(MONTH,PaymentDate) 
order by date;
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