How can I list all 1st row values in an Excel spre

Question

Using the OpenPyXL module with Python 3.5, I was able to figure out how many columns there are in a spreadsheet with:

In [1]: sheet.max_column
Out [1]: 4

Then I was able to list the values in each of the 4 cells with:

In [2]: for rowOfCellObjects in sheet['A1':'D1']:
            for cellObj in rowOfCellObjects:
                print(cellObj.coordinate, cellObj.value)
Out [2]: A1 Dog, B1 Cat, C1 Hamster, D1 Bigger Dog

But is there a way to skip the first step and simply list the values for x number of columns?

I wouldn't have known to iterate over ['A1':'D1] if I didn't know how many columns there were. If there were say 200 columns it would be a time waster to calculate the 200th letter/number after ['A1'].

Answer 1

Edit your sample to get what you want. But it's not recommended to do it this way!

for rowOfCellObjects in sheet['A1':sheet.cell(row=1, column=sheet.max_column).coordinate]:
      for cellObj in rowOfCellObjects:
          print(cellObj.coordinate, cellObj.value)

---

Use one of the following samples:

Sampel1: Iter all columns per row, break after the first row.

  for rows in ws.rows:
    for cell in rows:
      print('cell %s %s' % (cell.coordinate,cell.value))
    break

More programatical control:

Sample2: Iterates all columns only from the row given by min/max_row arguments, ends after one row.

Arguments min/max_row can point to any row, even also outside data.

  for rows in ws.iter_rows(min_row=1, max_row=1, min_col=1):
    for cell in rows:
      print('cell %s %s' % (cell.coordinate,cell.value))

* Tested with Python:3.4.2 - openpyxl:2.4.1 *

Answer 2

If you need to iterate through all the rows or columns of a file, you can instead use the openpyxl.worksheet.Worksheet.rows() property, or the openpyxl.worksheet.Worksheet.columns() property.

See Manipulating a workbook in memory.