How to translate a string of zeros and ones into b

Question

So I have this code snippet to translate a string into bitset.

    String huffmancode = "0010110100";
    char[] ch = huffmancode.toCharArray();

    BitSet bs = new BitSet();
    for (int i = 0; i < ch.length; i++)  {
        if (ch[i] == '1') {
            bs.set(i);
        }
    }

My question is how to determine the boundary / size / length of the bitset given that the first and the last indexes of huffman code were 0's ?

Answer 1

The following bitset contains [0,1] in order and the last line of the following code prints out 2, the length of the bitset.

BitSet bs = new BitSet();

bs.set(0, false);
bs.set(1, true);

System.out.println(bs.length());