How to find Current open Cursors in Oracle

2019-01-13 17:45发布

What is the query to find the no. of current open cursors in an Oracle Instance?

Also, what is the accuracy/update frequency of this data?

I am using Oracle 10gR2

6条回答
We Are One
2楼-- · 2019-01-13 18:16

1)your id should have sys dba access 2)

select sum(a.value) total_cur, avg(a.value) avg_cur, max(a.value) max_cur, 
 s.username, s.machine
 from v$sesstat a, v$statname b, v$session s 
 where a.statistic# = b.statistic# and s.sid=a.sid
 and b.name = 'opened cursors current' 
 group by s.username, s.machine
 order by 1 desc;
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迷人小祖宗
3楼-- · 2019-01-13 18:28

Oracle has a page for this issue with SQL and trouble shooting suggestions.

"Troubleshooting Open Cursor Issues" http://docs.oracle.com/cd/E40329_01/admin.1112/e27149/cursor.htm#OMADM5352

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贪生不怕死
4楼-- · 2019-01-13 18:30

Total cursors open, by session:

select a.value, s.username, s.sid, s.serial#
from v$sesstat a, v$statname b, v$session s
where a.statistic# = b.statistic#  and s.sid=a.sid
and b.name = 'opened cursors current';

Source: http://www.orafaq.com/node/758

As far as I know queries on v$ views are based on pseudo-tables ("x$" tables) that point directly to the relevant portions of the SGA, so you can't get more accurate than that; however this also means that it is point-in-time (i.e. dirty read).

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疯言疯语
5楼-- · 2019-01-13 18:32

Here's how to find open cursors that have been parsed. You need to be logged in as a user with access to v$open_cursor and v$session.

COLUMN USER_NAME FORMAT A15

SELECT s.machine, oc.user_name, oc.sql_text, count(1) 
FROM v$open_cursor oc, v$session s
WHERE oc.sid = s.sid
GROUP BY user_name, sql_text, machine
HAVING COUNT(1) > 2
ORDER BY count(1) DESC
;

If gives you part of the SQL text so it can be useful for identifying leaky applications. If a cursor has not been parsed, then it does not appear here. Note that Oralce will sometimes keep things open longer than you do.

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Ridiculous、
6楼-- · 2019-01-13 18:35

I use something like this:

select 
  user_name, 
  count(*) as "OPEN CURSORS" 
from 
  v$open_cursor 
group by 
  user_name;
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兄弟一词,经得起流年.
7楼-- · 2019-01-13 18:40
select  sql_text, count(*) as "OPEN CURSORS", user_name from v$open_cursor
group by sql_text, user_name order by count(*) desc;

appears to work for me.

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