How to delete an element from an array in C#

2019-01-01 05:28发布

Lets say I have this array,

int[] numbers = {1, 3, 4, 9, 2};

How can I delete an element by "name"? , lets say number 4?

Even ArrayList didn't help to delete?

string strNumbers = " 1, 3, 4, 9, 2";
ArrayList numbers = new ArrayList(strNumbers.Split(new char[] { ',' }));
numbers.RemoveAt(numbers.IndexOf(4));
foreach (var n in numbers)
{
    Response.Write(n);
}

标签: c# .net arrays
10条回答
有味是清欢
2楼-- · 2019-01-01 05:42
int[] numbers = { 1, 3, 4, 9, 2 };
numbers = numbers.Except(new int[]{4}).ToArray();
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残风、尘缘若梦
3楼-- · 2019-01-01 05:46

As a generic extension, 2.0-compatible:

using System.Collections.Generic;
public static class Extensions {
    //=========================================================================
    // Removes all instances of [itemToRemove] from array [original]
    // Returns the new array, without modifying [original] directly
    // .Net2.0-compatible
    public static T[] RemoveFromArray<T> (this T[] original, T itemToRemove) {  
        int numIdx = System.Array.IndexOf(original, itemToRemove);
        if (numIdx == -1) return original;
        List<T> tmp = new List<T>(original);
        tmp.RemoveAt(numIdx);
        return tmp.ToArray();
    }
}

Usage:

int[] numbers = {1, 3, 4, 9, 2};
numbers = numbers.RemoveFromArray(4);
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心情的温度
4楼-- · 2019-01-01 05:47

The code that is written in the question has a bug in it

Your arraylist contains strings of " 1" " 3" " 4" " 9" and " 2" (note the spaces)

So IndexOf(4) will find nothing because 4 is an int, and even "tostring" would convert it to of "4" and not " 4", and nothing will get removed.

An arraylist is the correct way to go to do what you want.

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梦该遗忘
5楼-- · 2019-01-01 05:52

If you want to remove all instances of 4 without needing to know the index:

LINQ: (.NET Framework 3.5)

int[] numbers = { 1, 3, 4, 9, 2 };
int numToRemove = 4;
numbers = numbers.Where(val => val != numToRemove).ToArray();

Non-LINQ: (.NET Framework 2.0)

static bool isNotFour(int n)
{
    return n != 4;
}

int[] numbers = { 1, 3, 4, 9, 2 };
numbers = Array.FindAll(numbers, isNotFour).ToArray();

If you want to remove just the first instance:

LINQ: (.NET Framework 3.5)

int[] numbers = { 1, 3, 4, 9, 2, 4 };
int numToRemove = 4;
int numIndex = Array.IndexOf(numbers, numToRemove);
numbers = numbers.Where((val, idx) => idx != numIndex).ToArray();

Non-LINQ: (.NET Framework 2.0)

int[] numbers = { 1, 3, 4, 9, 2, 4 };
int numToRemove = 4;
int numIdx = Array.IndexOf(numbers, numToRemove);
List<int> tmp = new List<int>(numbers);
tmp.RemoveAt(numIdx);
numbers = tmp.ToArray();

Edit: Just in case you hadn't already figured it out, as Malfist pointed out, you need to be targetting the .NET Framework 3.5 in order for the LINQ code examples to work. If you're targetting 2.0 you need to reference the Non-LINQ examples.

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唯独是你
6楼-- · 2019-01-01 05:54

' To remove items from string based on Dictionary key values. ' VB.net code

 Dim stringArr As String() = "file1,file2,file3,file4,file5,file6".Split(","c)
 Dim test As Dictionary(Of String, String) = New Dictionary(Of String, String)
 test.Add("file3", "description")
 test.Add("file5", "description")
 stringArr = stringArr.Except(test.Keys).ToArray()
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萌妹纸的霸气范
7楼-- · 2019-01-01 05:56

Removing from an array itself is not simple, as you then have to deal with resizing. This is one of the great advantages of using something like a List<int> instead. It provides Remove/RemoveAt in 2.0, and lots of LINQ extensions for 3.0.

If you can, refactor to use a List<> or similar.

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