I have written a code, for dynamically allocating a name. I know I should take care of deep copy in such scenarios. What I have written is my own version of Copy Constructor,Copy Assignment Operator and destructor. Should I redefine any other implicit functions such as Move Assignment Operator . I am not clear with the concept of Move Assignment Operator or any other implicitly defined member functions (other than which I have already mentioned ). Can any one please add the code for this dynName code
,to show Move assignment operator or any other implicit member function (if any).
#include <iostream>
using namespace std;
class dynName{
char* name;
int size;
public:
dynName(char* name="")
{
int n=strlen(name)+1;
this->name= new char[n];
strncpy(this->name,name,n);
size=n;
name[size-1]='\0';//NULL terminated
cout << "Object created (Constructor) with name : "
<< name << " at address " << &(this->name) << endl;
}
dynName(const dynName& Ob)//Copy Constructor
{
int n=Ob.size;
this->name= new char[n];
strncpy(this->name,Ob.name,n);
size=n;
cout << "Object created(Copy constructor) with name : "
<< this->name << " at address " << &(this->name) << endl;
}
//Assignment Operator
dynName& operator=(const dynName& ob);
~dynName()
{
cout << "Object with name " << this->name << " at address " <<
&(this->name)<<" destroyed" << endl;
delete[] name;
name=0; //Avoiding Dangling pointer if any
}
//friend ostream& operator << (ostream& os,const dynName ob);
//Will Call Copy Constructor
friend ostream& operator << (ostream& os,const dynName& ob);
};
dynName& dynName::operator=(const dynName& ob)
{
// check for self-assignment
if (this == &ob)
cout << "Created with assignment Operator " << endl;
return *this;
// first we need to deallocate any value that this string is holding!
delete[] this->name;
this->size = ob.size;
// this->name = new char[this->size];
strncpy(this->name, ob.name,this->size);
cout << "Created with assignment Operator " << endl;
return *this;
}
//ostream& operator << (ostream& os,const dynName ob)
ostream& operator << (ostream& os,const dynName& ob)
{
os << "The name ("<< ob.size << " Letters) : " << ob.name << endl;
return os;
}
int main()
{
dynName Ob1("Andrew Thomas");
dynName Ob2;
dynName Ob3(Ob1);
dynName Ob4;
Ob4=Ob1;//Should Call Assignment Operator
cout << "\n\n\n";
cout << Ob1;
cout << Ob2;
cout << Ob3;
cout << Ob4;
cout << "\n\n\n";
return 0;
}
The problem with this code is that it is not calling my copy assignment operator.Any help , why so ?
$ ./Trial
Object created (Constructor) with name : Andrew Thomas at address 0x22ac40
Object created (Constructor) with name : at address 0x22ac30
Object created(Copy constructor) with name : Andrew Thomas at address 0x22ac20
Object created (Constructor) with name : at address 0x22ac10
The name (14 Letters) : Andrew Thomas
The name (1 Letters) :
The name (14 Letters) : Andrew Thomas
The name (1 Letters) :
Object with name at address 0x22ac10 destroyed
Object with name Andrew Thomas at address 0x22ac20 destroyed
Object with name at address 0x22ac30 destroyed
Object with name Andrew Thomas at address 0x22ac40 destroyed
Thanks
EDIT
Referring to Move assignment operator and `if (this != &rhs)`
What is Class&&
? I mean I have never used something of this sort .. Just references i.e Class&
It should be calling the copy operator, but you always return after the self-assignment check.
It seems you are missing braces around here:
Only the output is part of the
if
body, thereturn
statement will always be executed.