How to replace all dots in a string using JavaScri

2019-01-01 04:46发布

I want to replace all the occurrences of a dot(.) in a JavaScript string

For example, I have:

var mystring = 'okay.this.is.a.string';

I want to get: okay this is a string.

So far I tried:

mystring.replace(/./g,' ')

but this ends up with all the string replaced to spaces.

14条回答
梦寄多情
2楼-- · 2019-01-01 05:33

you can replace all occurrence of any string/character using RegExp javasscript object.

Here is the code,

var mystring = 'okay.this.is.a.string';

var patt = new RegExp("\\.");

while(patt.test(mystring)){

  mystring  = mystring .replace(".","");

}
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人间绝色
3楼-- · 2019-01-01 05:34
/**
 * ReplaceAll by Fagner Brack (MIT Licensed)
 * Replaces all occurrences of a substring in a string
 */
String.prototype.replaceAll = function( token, newToken, ignoreCase ) {
    var _token;
    var str = this + "";
    var i = -1;

    if ( typeof token === "string" ) {

        if ( ignoreCase ) {

            _token = token.toLowerCase();

            while( (
                i = str.toLowerCase().indexOf(
                    _token, i >= 0 ? i + newToken.length : 0
                ) ) !== -1
            ) {
                str = str.substring( 0, i ) +
                    newToken +
                    str.substring( i + token.length );
            }

        } else {
            return this.split( token ).join( newToken );
        }

    }
return str;
};

alert('okay.this.is.a.string'.replaceAll('.', ' '));

Faster than using regex...

EDIT:
Maybe at the time I did this code I did not used jsperf. But in the end such discussion is totally pointless, the performance difference is not worth the legibility of the code in the real world, so my answer is still valid, even if the performance differs from the regex approach.

EDIT2:
I have created a lib that allows you to do this using a fluent interface:

replace('.').from('okay.this.is.a.string').with(' ');

See https://github.com/FagnerMartinsBrack/str-replace.

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