Find nearest value in numpy array

Question

Is there a numpy-thonic way, e.g. function, to find the nearest value in an array?

Example:

np.find_nearest( array, value )

Answer 1

import numpy as np
def find_nearest(array, value):
    array = np.asarray(array)
    idx = (np.abs(array - value)).argmin()
    return array[idx]

array = np.random.random(10)
print(array)
# [ 0.21069679  0.61290182  0.63425412  0.84635244  0.91599191  0.00213826
#   0.17104965  0.56874386  0.57319379  0.28719469]

value = 0.5

print(find_nearest(array, value))
# 0.568743859261

Answer 2

If you don't want to use numpy this will do it:

def find_nearest(array, value):
    n = [abs(i-value) for i in array]
    idx = n.index(min(n))
    return array[idx]

Answer 3

I think the most pythonic way would be:

 num = 65 # Input number
 array = n.random.random((10))*100 # Given array 
 nearest_idx = n.where(abs(array-num)==abs(array-num).min())[0] # If you want the index of the element of array (array) nearest to the the given number (num)
 nearest_val = array[abs(array-num)==abs(array-num).min()] # If you directly want the element of array (array) nearest to the given number (num)

This is the basic code. You can use it as a function if you want