Handle TokenMismatchException in laravel 5

2019-01-13 11:46发布

I need to handle TokenMismatchException in laravel 5 such a way that if token does not match it will show some message to user instead of TokenMismatchException error.

2条回答
手持菜刀,她持情操
2楼-- · 2019-01-13 12:11

You will need to write a function to render the TokenMismatchException error. You will add that function to your App\Exceptions\Handler class (in the /app/Exceptions/Handler.php file) this way:

// make sure you reference the full path of the class:
use Illuminate\Session\TokenMismatchException;

class Handler extends ExceptionHandler {

    protected $dontReport = [
        HttpException::class,
        ModelNotFoundException::class,
        // opt from logging this error to your log files (optional)
        TokenMismatchException::class,
    ];

    public function render($request, Exception $e)
    {
        // Handle the exception...
        // redirect back with form input except the _token (forcing a new token to be generated)
        if ($e instanceof TokenMismatchException){
            return redirect()->back()->withInput($request->except('_token'))
            ->withFlashDanger('You page session expired. Please try again');
        }
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神经病院院长
3楼-- · 2019-01-13 12:12

You can create a custom exception render in the App\Exceptions\Handler class (in the /app/Exceptions/Handler.php file).

For example, to render a different view when for the TokenMismatchException error, you can change the render method to something like this:

/**
 * Render an exception into an HTTP response.
 *
 * @param  \Illuminate\Http\Request  $request
 * @param  \Exception  $e
 * @return \Illuminate\Http\Response
 */
public function render($request, Exception $e)
{
    if ($e instanceof \Illuminate\Session\TokenMismatchException) {
        return response()->view('errors.custom', [], 500);
    }
    return parent::render($request, $e);
}
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