{var%20f='http://v.t.sina.com.cn/share/share.php?appkey=1515056452',u=z||d.location,p=['&url=',e(u),'&title=',e(t||d.title),'&source=',e(r),'&sourceUrl=',e(l),'&content=',c||'gb2312','&pic=',e(p||'')].join('');function%20a(){if(!window.open([f,p].join(''),'mb',['toolbar=0,status=0,resizable=1,width=440,height=430,left=',(s.width-440)/2,',top=',(s.height-430)/2].join('')))u.href=[f,p].join('');};if(/Firefox/.test(navigator.userAgent))setTimeout(a,0);else%20a();})(screen,document,encodeURIComponent,'','','https://www.manongdao.com/data/attach/logo/logo.png', '推荐 在下西门庆 的问题《Using XPath to select nodes outside of the normal》','https://www.manongdao.com/q-1108338.html','页面编码gb2312|utf-8默认gb2312'));){kind=link}
I have the following XML code:
<?xml version="1.0" encoding="UTF-8"?>
<Collection>
<Content>
<ID>12</ID>
<Type>Content</Type>
<Title>Office Location #1</Title>
<QuickLink>/office.aspx?id=12</QuickLink>
<Teaser>
<p>
<span class="infoBold">My Group</span>
<br />
WPO
<br />
Office Location #1
<br />
Wp, NY 090801
<br />
986.362.3265
</p>
</Teaser>
<Html>
<root>
<Location>
<location />
<office>WPO</office>
<Address>
<image>
<img src="someing.png" />
</image>
<Address1>Office Location #1</Address1>
<Address2 />
<City>Wp</City>
<State>NY</State>
<zip>09081</zip>
<phone>986.362.3265</phone>
<fax />
<urgent_care_phone />
</Address>
</Location>
</root>
</Html>
</Content>
<Content>
<ID>48</ID>
<Type>Content</Type>
<Title>Office Location #3</Title>
<QuickLink>/office.aspx?id=48</QuickLink>
<Teaser>
<p>
<span class="infoBold">My Group</span>
<br />
WPO
<br />
Office Location #3
<br />
Wp, NY 090801
<br />
986.362.3265
</p>
</Teaser>
<Html>
<root>
<Location>
<location />
<office>WPO</office>
<Address>
<image>
<img src="someing.png" />
</image>
<Address1>Office Location #3</Address1>
<Address2 />
<City>Wp</City>
<State>NY</State>
<zip>09081</zip>
<phone>986.362.3265</phone>
<fax />
<urgent_care_phone />
</Address>
</Location>
</root>
</Html>
</Content>
<Content>
<ID>36</ID>
<Type>Content</Type>
<Title>Office Location #2</Title>
<QuickLink>/office.aspx?id=36</QuickLink>
<Teaser>
<p>
<span class="infoBold">My Group</span>
<br />
WPO
<br />
Office Location #2
<br />
Wp, NY 090801
<br />
986.362.3265
</p>
</Teaser>
<Html>
<root>
<Location>
<location>WP</location>
<office>WPO</office>
<Address>
<image>
<img src="someing.png" />
</image>
<Address1>Office Location #2</Address1>
<Address2 />
<City>Wp</City>
<State>NY</State>
<zip>09081</zip>
<phone>986.362.3265</phone>
<fax />
<urgent_care_phone />
</Address>
</Location>
</root>
</Html>
</Content>
</Collection>
I want to display the following format:
FOR EACH ENTRY inside `Collection/Content/`:
Html/root/Location/location (if not blank show it)
Html/root/Location/Address {
/Address1
/Address2 (if not blank show it)
/City
/State
/zip
/phone
/fax (if not blank show it)
}
Html/root/Location/location (if not blank show it)
Html/root/Location/Address {
/Address1
/Address2 (if not blank show it)
/City
/State
/zip
/phone
/fax (if not blank show it)
}
Html/root/Location/location (if not blank show it)
Html/root/Location/Address {
/Address1
/Address2 (if not blank show it)
/City
/State
/zip
/phone
/fax (if not blank show it)
}
I am trying to get the QuickLink
<xsl:for-each select="Collection/Content/Html">
<div class="serviceHolder brClear">
<xsl:value-of select="root/Location/Address/Address1" />
<xsl:value-of select="root/Location/Address/Address2" />
<xsl:value-of select="root/Location/Address/City" />
<xsl:value-of select="root/Location/Address/State" />
<xsl:value-of select="root/Location/Address/zip" />
<xsl:value-of select="root/Location/Address/phone" />
<a href="{QuickLink}" title="Test">Get Direction</a>
</div>
</xsl:for-each>
Although I am using the Collection/Content/Html in the for-each, how do I go back to Collection/Content/QuickLink for the anchor link here:
<a href="{QuickLink}" title="Test">Get Direction</a>
For the
ageneration problem, make the XPath toQuickLinkrelative to the context node within thexsl:for-eachby changing:to
As for generating the rest of your pseudo markup in HTML by writing XSLT for you, I'd prefer to help with specific question rather than crank out code for you. Let us know if you have any other specific questions.