PHP URL Directory

Question

If the URL is the following :

If: http://www.imvu-e.com/products/dnr/
Then: http://www.imvu-e.com/products/dnr/

If: http://www.imvu-e.com/products/dnr/?
Then: http://www.imvu-e.com/products/dnr/

If: http://www.imvu-e.com/products/dnr/index.php
Then: http://www.imvu-e.com/products/dnr/

If: http://www.imvu-e.com/products/dnr/page.php?var=2
Then: http://www.imvu-e.com/products/dnr/

If: http://www.imvu-e.com/products/dnr
Then: http://www.imvu-e.com/products/

How can I do this?

My attempt:

print "http://".$_SERVER['HTTP_HOST'].dirname($_SERVER['REQUEST_URI'])."/";

Answer 1

Have a look at parse_url() function.

It returns anything you need.

Simply print_r() the result from parse_url to see what you get back. You probably want something like:

$ARRurlParts = parse_url($orgurl);

$newURL = $ARRelem["scheme"].
"://".$ARRelem["host"].
((isset($ARRelem["port"]))?":".$ARRelem["port"]:"").
$ARRelem["path"];

Answer 2

The issue with your "attempt" is that $_SERVER['REQUEST_URI'] will contain everything the user passed, including index.php and question mark and possibly more. In order to get what you are after, you need to parse the $_SERVER['REQUEST_URI']:

• If it ends with a slash /, leave it as it it
• Otherwise, find the last slash in the string and take the substring from the beginning up to and including this slash
• Finally append the result onto the http:// (or https:// with the domain name)

Answer 3

Ended up going with this

$s = empty($_SERVER["HTTPS"]) ? '' : ($_SERVER["HTTPS"] == "on") ? "s" : "";
$protocol = substr(strtolower($_SERVER["SERVER_PROTOCOL"]), 0, strpos(strtolower($_SERVER["SERVER_PROTOCOL"]), "/")) . $s;
$port = ($_SERVER["SERVER_PORT"] == "80") ? "" : (":".$_SERVER["SERVER_PORT"]);
$address = $protocol . "://" . $_SERVER['SERVER_NAME'] . $port . $_SERVER['REQUEST_URI'];
$parseUrl = parse_url(trim($address));
$parent = (substr($parseUrl['path'], -1) == '/') ? $parseUrl['path'] : dirname($parseUrl['path']) . "/";
return $parseUrl['scheme'] . '://' . $parseUrl['host'] . $parseUrl['port'] . $parent;

Inspired in part by Erwin Moller's answer (Why I voted it) and snipplets across web.

Answer 4

You can strip everything from the last backslash till the end of the string. I am pretty sure that dirname($_SERVER['REQUEST_URI']) won't do the job. You can also try using dirname($_SERVER['SCRIPT_FILENAME']). The last shoud work if you don't have some fancy .htaccess rewrite rules.