Listing files in Directory in Ubuntu

2019-09-06 13:45发布

I am trying to list files in the parent directory of the current directory, but when I try to execute this program from terminal I get Segmentation Error.. What am I doing wrong? Here is the code:

#include <stdio.h>
#include <stdlib.h>
#include <dirent.h>

int main(int argc, char *argv[])
{
   struct dirent *dirpent;
   DIR *dirp;

   if(argc!=2)
   {
       printf("Cant continue with the program\n");
       return 0;
   }

   dirp= opendir(argv[1]);

   if(dirp)
   {
       while(dirpent=readdir(dirp) !=NULL)
           printf("%s\n",dirpent->d_name);

       closedir(dirp);
   }
   return 0;
}

2条回答
甜甜的少女心
2楼-- · 2019-09-06 13:47
dirpent=readdir(dirp) !=NULL

should be

(dirpent = readdir(dirp)) != NULL

Your current expression is parsed as dirpent = (readdir(dirp) != NULL), which will set dirpent to either 0 or 1.

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我命由我不由天
3楼-- · 2019-09-06 13:52

If you indent your program with indent rd.c then compile your program with gcc -Wall -g rd.c -o rd you get

 rd.c: In function 'main':
 rd.c:21:22: warning: assignment makes pointer from integer without a cast [enabled by default]
 rd.c:21:7: warning: suggest parentheses around assignment used as truth value [-Wparentheses]

So you forgot parenthesis, your while should be

 while((dirpent=readdir(dirp)) !=NULL)

Please compile your program with all warnings (and improve it till they are all gone) before asking questions. Use the gdb debugger (and its bt command) to find out why a program crash with SIGSEGV.

Don't forget to carefully read documentation like readdir(3) man page and Advanced Linux Programming book.

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