Random element from array in Excel-VBA

2019-09-05 15:39发布

I've stormed the internet and still have not found any solution to this question:

I have an array like so;

Dim PayRate As Variant
PayRate = Array(10, 20, 30)

Cells(i, "E").value = PayRate(Int((2 - 1 + 1) * Rnd + 1))

but this will only give me 20 and 30 from the array (elements 1 and 2), I also want element 0 = 10 in the mix ? How do I got about doing that?

2条回答
兄弟一词,经得起流年.
2楼-- · 2019-09-05 15:53

Consider:

Sub dural()
Dim PayRate As Variant
PayRate = Array(10, 20, 30)
i = 1
N = Application.WorksheetFunction.RandBetween(LBound(PayRate), UBound(PayRate))
Cells(i, "E").Value = PayRate(N)
End Sub

I like this because it is independent of the number of elements in the array or whether it is zero-based or one-based.

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Viruses.
3楼-- · 2019-09-05 16:08

This will do it: Int(Rnd() * 3) + 1

Rnd() returns a uniformly distributed random number from and including 0 to and not including 1.

Important: you must have Option Base 1 at the top of the module so your PayRate array has lowest bound of 1. Seems like you have this given your question text.

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