Launching an application (.EXE) from C#?

Question

How can I launch an application using C#?

Requirements: Must work on Windows XP and Windows Vista.

I have seen a sample from DinnerNow.net sampler that only works in Windows Vista.

Answer 1

Just put your file.exe in the \bin\Debug folder and use:

Process.Start("File.exe");

Answer 2

Adame Kane

System.Diagnostics.Process.Start(@"C:\Windows\System32\Notepad.exe");

this worked great!!!!!

Answer 3

Try this:

Process.Start("Location Of File.exe");

(Make sure you use the System.Diagnostics library)

Answer 4

Use System.Diagnostics.Process.Start() method.

Check out this article on how to use it.

Answer 5

Here's a snippet of helpful code:

using System.Diagnostics;

// Prepare the process to run
ProcessStartInfo start = new ProcessStartInfo();
// Enter in the command line arguments, everything you would enter after the executable name itself
start.Arguments = arguments; 
// Enter the executable to run, including the complete path
start.FileName = ExeName;
// Do you want to show a console window?
start.WindowStyle = ProcessWindowStyle.Hidden;
start.CreateNoWindow = true;
int exitCode;


// Run the external process & wait for it to finish
using (Process proc = Process.Start(start))
{
     proc.WaitForExit();

     // Retrieve the app's exit code
     exitCode = proc.ExitCode;
}

There is much more you can do with these objects, you should read the documentation: ProcessStartInfo, Process.

Answer 6

Additionally you will want to use the Environment Variables for your paths if at all possible: http://en.wikipedia.org/wiki/Environment_variable#Default_Values_on_Microsoft_Windows

E.G.

• %WINDIR% = Windows Directory
• %APPDATA% = Application Data - Varies alot between Vista and XP.

There are many more check out the link for a longer list.