How to implement non-equi left outer join in hive involving more than two tables?
Query Used:
SELECT cs.SID, ins.ID, a.ID, e.id, i.id, cs.dateId, cs.timeId,cs.SSTRT,cs.SEND,cs.VAL,cs.IND,cs.TYP,cs.DTPE,cs.BCDE, cs.IVAL,cs.ICNT,cs.RDT,cs.REJ
from cs_item_hive cs
LEFT outer JOIN installation_hive ins ON (cs.SID=ins.SN)
LEFT OUTER JOIN account_hive a ON (ins.AID=a.ID AND ins.MDID = a.MDID)
LEFT OUTER JOIN equipment_hive e ON ins.GBLSID=e.GSN
LEFT OUTER JOIN item_hive i ON (cs.BCDE=i.ibc AND ins.MDID = i.MDID AND ins.AID = i.AID)
where cs.SEND >= ins.IDAT AND cs.SEND < ins.RDAT;
Issue:
Records that are not matching WHERE condition are skipped. [As, Hive does not support non-equi join, where condition is used]
Requirement:
Records that are not matching the condition should have the ins.ID, a.ID, e.id, i.id substituted as NULL [as like equi-join].
How to implement something like this in hive:
SELECT cs.SID, ins.ID, a.ID, e.id, i.id, cs.dateId, cs.timeId,cs.SSTRT,cs.SEND,cs.VAL,cs.IND,cs.TYP,cs.DTPE,cs.BCDE, cs.IVAL,cs.ICNT,cs.RDT,cs.REJ
from cs_item_hive cs
LEFT outer JOIN installation_hive ins ON (cs.SID=ins.SN AND cs.SEND >= ins.IDAT AND cs.SEND < ins.RDAT)
LEFT OUTER JOIN account_hive a ON (ins.AID=a.ID AND ins.MDID = a.MDID)
LEFT OUTER JOIN equipment_hive e ON ins.GBLSID=e.GSN
LEFT OUTER JOIN item_hive i ON (cs.BCDE=i.ibc AND ins.MDID = i.MDID AND ins.AID = i.AID);
Please guide me to resolve this issue.
Thankyou.
You can come pretty close with:
Alternatively, I think you can use two queries, one for matches and one for non-matches.