This question already has an answer here:
There are two ways to allocate memory to an array, of which the size is unknown at the beginning. The most common way is using malloc
like this
int * array;
... // when we know the size
array = malloc(size*sizeof(int));
But it's valid too in C99 to define the array after we know the size.
... // when we know the size
int array[size];
Are they absolutely the same?
No they're not absolutely the same. While both let you store the same number and type of objects, keep in mind that:
free()
a malloced array, but you can'tfree()
a variable length array (although it goes out of scope and ceases to exist once the enclosing block is left). In technical jargon, they have different storage duration: allocated for malloc versus automatic for variable length arrays.malloc
allocates from the heap. This is an issue on stack-limited systems, e.g. many embedded operating systems, where the stack size is on the order of kB, while the heap is much larger.malloc
than with a variable length array.realloc()
, while VLAs can't (more precisely only by executing the block again with a different array dimension--which loses the previous contents).malloc()
.__STDC_NO_VLA__
as the integer 1 according to C11 6.10.8.3).