I have a C program, where I just wanted to test if I could reproduce a console spinner used in npm install
while it installs a module. This particular spinner simply spins in this order:
|
/
-
\
on the same space, so I use the following program:
#include <stdio.h>
int main() {
char sequence[4] = "|/-\\";
while(1) {
for(int i = 0; i < 4; i++) {
// \b is to make the character print to the same space
printf("\b%c", sequence[i]);
// now I want to delay here ~0.25s
}
}
}
So I found a way to make it rest for that long from <time.h> documentation and made this program:
#include <stdio.h>
#include <time.h>
void sleep(double seconds) {
clock_t then;
then = clock();
while(((double)(clock() - then) / CLOCKS_PER_SEC) < seconds); //do nothing
}
int main() {
char sequence[4] = "|/-\\";
while(1) {
for(int i = 0; i < 4; i++) {
printf("\b%c", sequence[i]);
sleep(0.25);
}
}
}
But now nothing prints to the console. Does anyone know how I can go about producing the behavior I want?
EDIT According to what appears to be popular opinion, I've updated my code above to be the following:
#include <stdio.h>
#include <unistd.h>
int main() {
char sequence[4] = "|/-\\";
while(1) {
for(int i = 0; i < 4; i++) {
printf("\b%c", sequence[i]);
/* fflush(stdout); */
// commented out to show same behavior as program above
usleep(250000); // 250000 microseconds = 0.25 seconds
}
}
}
Things do get printed to console, it's just does not get flushed. Add
fflush(stdout)
to see the results, or set the console in an unbuffered mode by callingsetbuf
:A bigger problem with your code is that your
sleep
method runs a busy loop, which burns CPU cycles for no good reason. A better alternative would be to callusleep
, which takes the number of microseconds:You will need to flush after you wrote to the console. Otherwise, the program will buffer your output:
The sleep function isn't really your problem. The issue is that the output is buffered. The simplest thing to do will be to research ncurses.
For now: