os.walk without digging into directories below

Question

How do I limit os.walk to only return files in the directory I provide it?

def _dir_list(self, dir_name, whitelist):
    outputList = []
    for root, dirs, files in os.walk(dir_name):
        for f in files:
            if os.path.splitext(f)[1] in whitelist:
                outputList.append(os.path.join(root, f))
            else:
                self._email_to_("ignore")
    return outputList

Answer 1

I think the solution is actually very simple.

use

break

to only do first iteration of the for loop, there must be a more elegant way.

for root, dirs, files in os.walk(dir_name):
    for f in files:
        ...
        ...
    break
...

The first time you call os.walk, it returns tulips for the current directory, then on next loop the contents of the next directory.

Take original script and just add a break.

def _dir_list(self, dir_name, whitelist):
    outputList = []
    for root, dirs, files in os.walk(dir_name):
        for f in files:
            if os.path.splitext(f)[1] in whitelist:
                outputList.append(os.path.join(root, f))
            else:
                self._email_to_("ignore")
        break
    return outputList

Answer 2

Don't use os.walk.

Example:

import os

root = "C:\\"
for item in os.listdir(root):
    if os.path.isfile(os.path.join(root, item)):
        print item

Answer 3

This is how I solved it

if recursive:
    items = os.walk(target_directory)
else:
    items = [next(os.walk(target_directory))]

...

Answer 4

You could also do the following:

for path, subdirs, files in os.walk(dir_name):
    for name in files:
        if path == ".": #this will filter the files in the current directory
             #code here