os.walk without digging into directories below

Question

How do I limit os.walk to only return files in the directory I provide it?

def _dir_list(self, dir_name, whitelist):
    outputList = []
    for root, dirs, files in os.walk(dir_name):
        for f in files:
            if os.path.splitext(f)[1] in whitelist:
                outputList.append(os.path.join(root, f))
            else:
                self._email_to_("ignore")
    return outputList

Answer 1

create a list of excludes, use fnmatch to skip the directory structure and do the process

excludes= ['a\*\b', 'c\d\e']
for root, directories, files in os.walk('Start_Folder'):
    if not any(fnmatch.fnmatch(nf_root, pattern) for pattern in excludes):
        for root, directories, files in os.walk(nf_root):
            ....
            do the process
            ....

same as for 'includes':

if **any**(fnmatch.fnmatch(nf_root, pattern) for pattern in **includes**):

Answer 2

In Python 3, I was able to do this:

import os
dir = "/path/to/files/"

#List all files immediately under this folder:
print ( next( os.walk(dir) )[2] )

#List all folders immediately under this folder:
print ( next( os.walk(dir) )[1] )

Answer 3

Why not simply use a range and os.walk combined with the zip? Is not the best solution, but would work too.

For example like this:

# your part before
for count, (root, dirs, files) in zip(range(0, 1), os.walk(dir_name)):
    # logic stuff
# your later part

Works for me on python 3.

Also: A break is simpler too btw. (Look at the answer from @Pieter)

Answer 4

You can use this snippet

for root, dirs, files in os.walk(directory):
    if level > 0:
        # do some stuff
    else:
        break
    level-=1

Answer 5

The suggestion to use listdir is a good one. The direct answer to your question is root, dirs, files = os.walk(dir_name).next()

Answer 6

The same idea with listdir, but shorter:

[f for f in os.listdir(root_dir) if os.path.isfile(os.path.join(root_dir, f))]