Program runs once and it both throws data to the pipe and gets it out in the same condition that should be mutually exclusive (in if and else). What I don't get here? How does that work? I have no experience with this kind of programming.
#include <sys/types.h>
#include <unistd.h>
#include <stdio.h>
#include <stdlib.h>
Read characters from the pipe and echo them to stdout.
void
read_from_pipe (int file)
{
FILE *stream;
int c;
stream = fdopen (file, "r");
while ((c = fgetc (stream)) != EOF)
putchar (c);
fclose (stream);
}
Write some random text to the pipe.
void
write_to_pipe (int file)
{
FILE *stream;
stream = fdopen (file, "w");
fprintf (stream, "hello, world!\n");
fprintf (stream, "goodbye, world!\n");
fclose (stream);
}
int
main (void)
{
pid_t pid;
int mypipe[2];
/* Create the pipe. */
if (pipe (mypipe))
{
fprintf (stderr, "Pipe failed.\n");
return EXIT_FAILURE;
}
/* Create the child process. */
pid = fork ();
if (pid == (pid_t) 0)
{
/* This is the child process.
Close other end first. */
close (mypipe[1]);
read_from_pipe (mypipe[0]);
return EXIT_SUCCESS;
}
else if (pid < (pid_t) 0)
{
/* The fork failed. */
fprintf (stderr, "Fork failed.\n");
return EXIT_FAILURE;
}
else
{
/* This is the parent process.
Close other end first. */
close (mypipe[0]);
write_to_pipe (mypipe[1]);
return EXIT_SUCCESS;
}
}
Right after the line that says:
You no longer have one program, but two distinct ones (when
fork
succeeds).It's not the same program that runs both. In the child process,
fork
returns 0, but in the parent it returns the child PID.The parent runs one branch of the
if
/else
construct, the child runs another. (And a third is run, in the parent only, iffork
fails.)