Is it possible to determine whether ViewController

Question

Is it possible to check inside ViewController class that it is presented as modal view controller?

Answer 1

Since modalViewController has been deprecated in iOS 6, here's a version that works for iOS 5+ and that compiles without warnings.

Objective-C:

- (BOOL)isModal {
    return self.presentingViewController.presentedViewController == self
      || (self.navigationController != nil && self.navigationController.presentingViewController.presentedViewController == self.navigationController)
      || [self.tabBarController.presentingViewController isKindOfClass:[UITabBarController class]];
}

Swift:

var isModal: Bool {
    return self.presentingViewController?.presentedViewController == self
        || (self.navigationController != nil && self.navigationController?.presentingViewController?.presentedViewController == self.navigationController)
        || self.tabBarController?.presentingViewController is UITabBarController
}

Hat tip to Felipe's answer.

Answer 2

Best way to check

 if (self.navigationController.presentingViewController) {
         NSLog(@"Model Present");
    }

Answer 3

In my project I have a view controller (Detail) that can be presented either modally (when adding a new item) or with push (when editing an existing one) by Master view controller. When user taps [Done] the Detail view controller calls Master view controller's method to notify that it is ready to be closed. Master has to determine how Detail is presented in order to know how to close it. This is how I do this:

UIViewController *vc = self.navigationController.viewControllers.lastObject;
if (vc == self) {
    [self dismissViewControllerAnimated:YES completion:NULL];
} else {
    [self.navigationController popViewControllerAnimated:YES];
}

Answer 4

Petronella's answer does not work if self.navigationController is modally presented but self is not equal to self.navigationController.viewControllers[0], in that case self is pushed.

Here is how you could fix the problem.

return self.presentingViewController.presentedViewController == self
            || (self.navigationController != nil && self.navigationController.presentingViewController.presentedViewController == self.navigationController && self == self.navigationController.viewControllers[0])
            || [self.tabBarController.presentingViewController isKindOfClass:[UITabBarController class]];

And in Swift:

return self.presentingViewController?.presentedViewController == self
        || (self.navigationController != nil && self.navigationController?.presentingViewController?.presentedViewController == self.navigationController && self.navigationController?.viewControllers[0] == self)
        || self.tabBarController?.presentingViewController is UITabBarController

Answer 5

Here's my modified version of @GabrielePetronella's isModal, which works with contained view controllers in that it walks up the parentViewController hierarchy first. Also pulled the code out into multiple lines so it's clear what it's doing.

var isModal: Bool {
    // If we are a child view controller, we need to check our parent's presentation
    // rather than our own.  So walk up the chain until we don't see any parentViewControllers
    var potentiallyPresentedViewController : UIViewController = self
    while (potentiallyPresentedViewController.parentViewController != nil) {
        potentiallyPresentedViewController = potentiallyPresentedViewController.parentViewController!
    }

    if self.presentingViewController?.presentedViewController == potentiallyPresentedViewController {
        return true
    }

    if let navigationController = potentiallyPresentedViewController.navigationController {
        if navigationController.presentingViewController?.presentedViewController == navigationController {
            return true
        }
    }

    return potentiallyPresentedViewController.tabBarController?.presentingViewController is UITabBarController
}

Answer 6

A hack like this might work.

UIViewController* child = self;
UIViewController* parent = child.parentViewController;
while (parent && parent.modalViewController != child) {
    child = parent;
    parent = child.parentViewController;
}
if (parent) {
    // A view controller in the hierarchy was presented as a modal view controller
}

However, I think my previous answer is a cleaner solution.