Open xml file with different extension using loadX

Question

I've got a file with an extension of .abc which is an XML file and I am processing the XML using XSL.

I open an HTML page which loads the XML using loadXMLDoc like this:

xml=loadXMLDoc("Example.xml");  
xsl=loadXMLDoc("Example.xsl");

The problem is I need to open "Example.abc" not "Example.xml". If I try:

xml=loadXMLDoc("Example.abc");

the page loads but with no data.

Is there a way I can load the .abc file?

Answer 1

It is not clear exactly what you are referring to here.

Do you mean the loadXMLDoc function that is introducted here at w3Schools.com?

function loadXMLDoc(dname)
{
if (window.XMLHttpRequest)
  {
  xhttp=new XMLHttpRequest();
  }
else
  {
  xhttp=new ActiveXObject("Microsoft.XMLHTTP");
  }
xhttp.open("GET",dname,false);
xhttp.send("");
return xhttp.responseXML;
} 

I just tried playing around with this and it works perfectly well with any file extension for the .xml - one thing I did notice is that the browser was caching the html so that I had to close and reopen the page (when it was just on my desktop) to refresh the file name I had.

Could this be your issue?

Answer 2

Did have the same problem. XMLHttpRequest.get requires a xml mime type. To solve this, insert

if (xhttp.overrideMimeType)  xhttp.overrideMimeType("text/xml");

before the xhttp.open("GET", dname, false); line in the xsl file