I would like to parse entries for mines from industryAbout. In this example I'm working on the Kevitsa Copper Concentrator.
The interesting block in the HTML is:
<strong>Commodities: Copper, Nickel, Platinum, Palladium, Gold</strong><br /><strong>Area: Lappi</strong><br /><strong>Type: Copper Concentrator Plant</strong><br /><strong>Annual Production: 17,200 tonnes of Copper (2015), 8,800 tonnes of Nickel (2015), 31,900 tonnes of Platinum, 25,100 ounces of Palladium, 12,800 ounces of Gold (2015)</strong><br /><strong>Owner: Kevitsa Mining Oy</strong><br /><strong>Shareholders: Boliden AB (100%)</strong><br /><strong>Activity since: 2012</strong>
I've written a (basic) working parser, which gives me
<strong>Commodities: Copper, Nickel, Platinum, Palladium, Gold</strong>
<strong>Area: Lappi</strong>
<strong>Type: Copper Concentrator Plant</strong>
....
But I would like to get $commodities, $type, $annual_production, $shareholders and $actitivity as separate variables. How can I do this? Regular expressions??
import requests
from bs4 import BeautifulSoup
import re
page = requests.get("https://www.industryabout.com/country-territories-3/2199-finland/copper-mining/34519-kevitsa-copper-concentrator-plant")
soup = BeautifulSoup(page.content, 'lxml')
rows = soup.select("strong")
for r in rows:
print(r)
2nd version:
import requests
from bs4 import BeautifulSoup
import re
import csv
links = ["34519-kevitsa-copper-concentrator-plant", "34520-kevitsa-copper-mine", "34356-glogow-copper-refinery"]
for l in links:
page = requests.get("https://www.industryabout.com/country-territories-3/2199-finland/copper-mining/"+l)
soup = BeautifulSoup(page.content, 'lxml')
rows = soup.select("strong")
d = {}
for r in rows:
name, value, *rest = r.text.split(":")
if not rest:
d[name] = value
print(d)
Does this do what you want?: