I have the following XML and I want to get only the element names that start with "MBH":
<?xml version="1.0" encoding="UTF-8"?>
<GenericRecs>
<GenericRecord>
<record>
<MBH1/>
</record>
<record>
<BAL1/>
</record>
<record>
<MBH2/>
</record>
<record>
<BAL2/>
</record>
<record>
<PAY2/>
</record>
<record>
<MBH3/>
</record>
<record>
<BAL3/>
</record>
<record>
<PAY3/>
</record>
</GenericRecord>
</GenericRecs>
I have the following XSLT:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:ext="http://exslt.org/common"
version="1.0">
<xsl:variable name="x" select="ext:node-set(substring(local-name(//record/child::*),1,3)='MBH')"/>
<xsl:variable name="mbh">
<xsl:for-each select="$x">
<item>
<xsl:copy>
<xsl:value-of select="local-name(.)"/>
</xsl:copy>
</item>
</xsl:for-each>
</xsl:variable>
<xsl:template match="/">
<xsl:apply-templates select="$mbh"/>
</xsl:template>
</xsl:stylesheet>
But all I get is an error "Description: Can not convert #RTREEFRAG to a NodeList!" I am using EXSLT but I do not understand why I would get that error.
Thank you for your help, Peter
What's wrong with
?
A few notes:
name()
rather thanlocal-name()
whenever possible. There are no namespaces in your input so there is no difference between them anyway.child::
axis is the default.child::*
is equivalent to*
.<xyz1>
through<xyz3>
is not very clever, unless<xyz3>
actually is completely different from<xyz1>
(instead of merely being "the third<xyz>
").In that case
<xyz num="1">
would be sensible. If they are completely different, they should not have a similar name.